"aaa", "3[aaa]",
		"aa", "2[aa]",
		"a", "1[a]",
		"i", "i",
		"longerst", "most long",
		"longer", "medium",
		"long", "short",
		"xx", "xx",
		"x", "X",
		"X", "Y",
		"Y", "Z",
	)
	testCases = append(testCases,
		testCase{gen1, "fooaaabar", "foo3[aaa]b1[a]r"},
		testCase{gen1, "long, longerst, longer", "short, most long, medium"},
		testCase{gen1, "xxxxx", "xxxxX"},

tests-longest.png...

                new StyledTable.Row(["tiny", "even longer"], StyledTextOutput.Style.Normal)
            ]
        )

        expect:
        StyledTableUtil.toString(table) == """
            | a         | b           |
            |-----------|-------------|
            | foo       | bar         |
            | very long | short       |
            | tiny      | even longer |
        """.stripIndent(true).trim()
    }

			}
			if old := b.matchcap[1]; old == -1 || (longest && pos > 0 && pos > old) {
				copy(b.matchcap, b.cap)
			}

			// If going for first match, we're done.
			if !longest {
				return true
			}

			// If we used the entire text, no longer match is possible.
			if pos == b.end {
				return true
			}

			// Otherwise, continue on in hope of a longer match.
			continue
		}
	}

# 'go mod tidy' would arbitrarily choose the one with the longer path,
# but 'go mod tidy' also arbitrarily chooses the latest version.

cp go.mod go.mod.orig


# From a clean slate, 'go get' currently does the same thing as 'go mod tidy':
# it resolves the package from the module with the longest matching prefix.

go get example.net/ambiguous/nested/pkg@v0.1.0
go list -m all

        // We've chosen a connection to evict. Confirm it's still okay to be evicted, then close it.
        toEvict.withLock {
          if (toEvict.calls.isNotEmpty()) return 0L // No longer idle.
          if (toEvict.idleAtNs != toEvictIdleAtNs) return 0L // No longer oldest.
          toEvict.noNewExchanges = true
          connections.remove(toEvict)
        }
        addressStates[toEvict.route.address]?.scheduleOpener()

}

/** Encodes an IPv6 address in canonical form according to RFC 5952. */
internal fun inet6AddressToAscii(address: ByteArray): String {
  // Go through the address looking for the longest run of 0s. Each group is 2-bytes.
  // A run must be longer than one group (section 4.2.2).
  // If there are multiple equal runs, the first one must be used (section 4.2.3).
  var longestRunOffset = -1
  var longestRunLength = 0
  run {

	// This field can be modified by the Longest method,
	// but it is otherwise read-only.
	longest bool // whether regexp prefers leftmost-longest match
}

// String returns the source text used to compile the regular expression.
func (re *Regexp) String() string {
	return re.expr
}

// Copy returns a new [Regexp] object copied from re.
// Calling [Regexp.Longest] on one copy does not affect another.
//

		l[len(l)-1] += "\n\\ No newline at end of file\n"
	}
	return l
}

// tgs returns the pairs of indexes of the longest common subsequence
// of unique lines in x and y, where a unique line is one that appears
// once in x and once in y.
//
// The longest common subsequence algorithm is as described in
// Thomas G. Szymanski, “A Special Case of the Maximal Common

	re.longest = false
	return re.MatchString(text), ""
}

func matchFullLongest(re, refull *Regexp, text string) (bool, string) {
	refull.longest = true
	return refull.MatchString(text), "[full,longest]"
}

func matchPartialLongest(re, refull *Regexp, text string) (bool, string) {
	re.longest = true
	return re.MatchString(text), "[longest]"
}