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Results 1 - 1 of 1 for log10 (0.14 sec)

  1. android/guava/src/com/google/common/math/LongMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Java
    - Registered: Fri Apr 26 12:43:10 GMT 2024
    - Last Modified: Wed Feb 07 17:50:39 GMT 2024
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