* byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

    Random random = new Random(7);
    List<HashCode> hashCodes = new ArrayList<>();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

    Random random = new Random(7);
    List<HashCode> hashCodes = new ArrayList<>();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

      if (hash != other.hash) return false

      return true
    }

    override fun hashCode(): Int {
      var result = pattern.hashCode()
      result = 31 * result + hashAlgorithm.hashCode()
      result = 31 * result + hash.hashCode()
      return result
    }
  }

  /** Builds a configured certificate pinner. */
  class Builder {

        // Same inputs and output should have same hash code
        assertEquals(item1.hashCode(), item2.hashCode());

        // Different inputs should have different hash code
        assertNotSame(item1.hashCode(), item3.hashCode());

        // Same inputs but different output should have different hash code
        assertNotSame(item1.hashCode(), item4.hashCode());
    }

    public void test_equals() {

            UniAddress uniAddress1 = new UniAddress(inetAddress1);
            assertEquals(inetAddress1.hashCode(), uniAddress1.hashCode());

            UniAddress uniAddress2 = new UniAddress(nbtAddress1);
            assertEquals(nbtAddress1.hashCode(), uniAddress2.hashCode());
        }

        @Test
        void equalsShouldReturnTrueForSameWrappedAddress() {

        result = 31 * result + a.getGroupId().hashCode();
        result = 31 * result + a.getArtifactId().hashCode();
        result = 31 * result + a.getType().hashCode();
        if (a.getVersion() != null) {
            result = 31 * result + a.getVersion().hashCode();
        }
        result = 31 * result + (a.getClassifier() != null ? a.getClassifier().hashCode() : 0);

                             * augment the addresses name's hashCode to distinguish those resolved by
                             * Lmhosts, WINS, or BCAST. Otherwise a failed query from say WINS would
                             * get pulled out of the cache for a BCAST on the same name.
                             */
                            response.addrEntry[0].hostName.srcHashCode = request.addr.hashCode();