* byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

   * byte-based hashcode. Otherwise it returns {@link HashCode#asBytes}. Do <i>not</i> mutate this
   * array or else you will break the immutability contract of {@code HashCode}.
   */
  byte[] getBytesInternal() {
    return asBytes();
  }

  /**
   * Returns whether this {@code HashCode} and that {@code HashCode} have the same value, given that

      assertErrorMessage(
          e,
          "the Object#hashCode ("
              + a.hashCode()
              + ") of "
              + a
              + " [group 1, item 1] must be equal to the Object#hashCode ("
              + b.hashCode()
              + ") of "
              + b);
      return;
    }
    fail("Should get invalid hashCode error");
  }

  public void testNullEqualityGroup() {

    Random random = new Random(7);
    List<HashCode> hashCodes = Lists.newArrayList();
    for (int i = 0; i < 10; i++) {
      hashCodes.add(HashCode.fromLong(random.nextLong()));
    }
    HashCode hashCode1 = Hashing.combineOrdered(hashCodes);
    Collections.shuffle(hashCodes, random);
    HashCode hashCode2 = Hashing.combineOrdered(hashCodes);

    assertFalse(hashCode1.equals(hashCode2));
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

    bytesB[4] = (byte) 0xef;

    HashCode hashCodeA = HashCode.fromBytes(bytesA);
    HashCode hashCodeB = HashCode.fromBytes(bytesB);

    // They aren't equal...
    assertFalse(hashCodeA.equals(hashCodeB));

    // But they still have the same Object#hashCode() value.
    // Technically not a violation of the equals/hashCode contract, but...?
    assertEquals(hashCodeA.hashCode(), hashCodeB.hashCode());
  }

      if (hash != other.hash) return false

      return true
    }

    override fun hashCode(): Int {
      var result = pattern.hashCode()
      result = 31 * result + hashAlgorithm.hashCode()
      result = 31 * result + hash.hashCode()
      return result
    }
  }

  /** Builds a configured certificate pinner. */
  class Builder {

              @Override
              public Set<Entry<String, String>> entrySet() {
                return new EntrySet();
              }

              @Override
              public int hashCode() {
                return map.hashCode();
              }

              @Override
              public boolean equals(@Nullable Object o) {
                return map.equals(o);
              }

              @Override

 * augment the addresses name's hashCode to distinguish those resolved by
 * Lmhosts, WINS, or BCAST. Otherwise a failed query from say WINS would
 * get pulled out of the cache for a BCAST on the same name.
 */
                                response.addrEntry[0].hostName.srcHashCode =
                                                        request.addr.hashCode();
                                return response.addrEntry[0];

   * java.util.HashMap class.
   */
  // Copied from java/com/google/common/collect/Hashing.java
  private static int smear(int hashCode) {
    hashCode ^= (hashCode >>> 20) ^ (hashCode >>> 12);
    return hashCode ^ (hashCode >>> 7) ^ (hashCode >>> 4);
  }

  private static class PaddedLock extends ReentrantLock {
    /*