*/
  static double calculateNewMeanNonFinite(double previousMean, double value) {
    /*
     * Desired behaviour is to match the results of applying the naive mean formula. In particular,
     * the update formula can subtract infinities in cases where the naive formula would add them.
     *
     * Consequently:
     * 1. If the previous mean is finite and the new value is non-finite then the new mean is that

     * numHashFunctions/bitSize)^n)`. Solving that for n, and approximating `ln x` as `x - 1` when x
     * is close to 1 (why?), gives the following formula.
     */
    double fractionOfBitsSet = (double) bitCount / bitSize;
    return DoubleMath.roundToLong(
        -Math.log1p(-fractionOfBitsSet) * bitSize / numHashFunctions, RoundingMode.HALF_UP);
  }

        if (!(element instanceof Long) || parent.array[i++] != (Long) element) {
          return false;
        }
      }
      return true;
    }

    // Because we happen to use the same formula. If that changes, just don't override this.
    @Override
    public int hashCode() {
      return parent.hashCode();
    }

    @Override
    public String toString() {
      return parent.toString();

        if (!(element instanceof Integer) || parent.array[i++] != (Integer) element) {
          return false;
        }
      }
      return true;
    }

    // Because we happen to use the same formula. If that changes, just don't override this.
    @Override
    public int hashCode() {
      return parent.hashCode();
    }

    @Override
    public String toString() {
      return parent.toString();

        if (!(element instanceof Integer) || parent.array[i++] != (Integer) element) {
          return false;
        }
      }
      return true;
    }

    // Because we happen to use the same formula. If that changes, just don't override this.
    @Override
    public int hashCode() {
      return parent.hashCode();
    }

    @Override
    public String toString() {
      return parent.toString();

        if (!(element instanceof Double) || !areEqual(parent.array[i++], (Double) element)) {
          return false;
        }
      }
      return true;
    }

    // Because we happen to use the same formula. If that changes, just don't override this.
    @Override
    public int hashCode() {
      return parent.hashCode();
    }

    @Override
    public String toString() {
      return parent.toString();

	}
	in.macros[name] = &Macro{
		name:   name,
		args:   args,
		tokens: tokens,
	}
}

// macroDefinition returns the list of formals and the tokens of the definition.
// The argument list is nil for no parens on the definition; otherwise a list of
// formal argument names.
func (in *Input) macroDefinition(name string) ([]string, []Token) {
	prevCol := in.Stack.Col()
	tok := in.Stack.Next()

Daten aus Formularen werden, wenn es keine Dateien sind, normalerweise mit dem <abbr title='Media type – Medientyp, Typ des Mediums'>„media type“</abbr> `application/x-www-form-urlencoded` kodiert.

Sollte das Formular aber Dateien enthalten, dann werden diese mit `multipart/form-data` kodiert. Wenn Sie `File` verwenden, wird **FastAPI** wissen, dass es die Dateien vom korrekten Teil des Bodys holen muss.

     *
     * @param formal the formal parameter type to which the actual
     *               parameter type should be convertible
     * @param actual the actual parameter type.
     * @return true if either formal type is assignable from actual type,
     *         or formal and actual are both primitive types and actual can be
     *         subject to widening conversion to formal.
     */

  }

  /**
   * Returns a new {@code TypeResolver} with type variables in {@code formal} mapping to types in
   * {@code actual}.
   *
   * <p>For example, if {@code formal} is a {@code TypeVariable T}, and {@code actual} is {@code
   * String.class}, then {@code new TypeResolver().where(formal, actual)} will {@linkplain
   * #resolveType resolve} {@code ParameterizedType List<T>} to {@code List<String>}, and resolve