* worker processes: worker processes (do not translate to "procesos trabajadores" or "procesos de trabajo")
* worker: worker (do not translate to "trabajador")
* load balancer: load balancer (do not translate to "balanceador de carga")
* load balance: load balance (do not translate to "balancear carga")

You could load it at the top level of the module/file, but that would also mean that it would **load the model** even if you are just running a simple automated test, then that test would be **slow** because it would have to wait for the model to load before being able to run an independent part of the code.

DOWNLOADS="$(mktemp -d)"
mkdir -p "$DOWNLOADS"
gsutil -m rsync -r "$TFCI_ARTIFACT_STAGING_GCS_URI" "$DOWNLOADS"
ls "$DOWNLOADS"

# Upload all build artifacts to e.g. gs://tensorflow/versions/2.16.0-rc1 (releases) or
# gs://tensorflow/nightly/2.16.0-dev20240105 (nightly), overwriting previous values.
if [[ "$TFCI_ARTIFACT_FINAL_GCS_ENABLE" == 1 ]]; then

## How to enable Fan-Out Uploads ?

          retention-days: 5

      # Upload the results to GitHub's code scanning dashboard (optional).
      # Commenting out will disable upload of results to your repo's Code Scanning dashboard
      - name: "Upload to code-scanning"
        uses: github/codeql-action/upload-sarif@3c3833e0f8c1c83d449a7478aa59c036a9165498 # v3.29.5
        with:

You can also use `File()` with `UploadFile`, for example, to set additional metadata:

{* ../../docs_src/request_files/tutorial001_03_an_py39.py hl[9,15] *}

## Multiple File Uploads { #multiple-file-uploads }

It's possible to upload several files at the same time.

They would be associated to the same "form field" sent using "form data".

To use that, declare a list of `bytes` or `UploadFile`:

	}
	return
}

// Parse bucket url queries for ?uploads
func getBucketMultipartResources(values url.Values) (prefix, keyMarker, uploadIDMarker, delimiter string, maxUploads int, encodingType string, errCode APIErrorCode) {
	errCode = ErrNone

	if values.Get("max-uploads") != "" {
		var err error
		if maxUploads, err = strconv.Atoi(values.Get("max-uploads")); err != nil {
			errCode = ErrInvalidMaxUploads
			return
		}

					if asyncErr == nil {
						asyncErr = err
					}
					asyncErrMu.Unlock()
				}
			}(name, header.FileInfo(), b)
			continue
		}

		// If zero or earlier modtime, set to current.
		// Otherwise the resulting objects will be invalid.
		if header.ModTime.UnixNano() <= 0 {
			header.ModTime = time.Now()
		}

		// Sync upload.
		rc := disconnectReader{r: tarReader}

		}
	}
}

const (
	subnetHealthPath = "/api/health/upload"
)

func sendHealthInfo(ctx context.Context, healthInfo madmin.HealthInfo) error {
	url := globalSubnetConfig.BaseURL + subnetHealthPath

	filename := fmt.Sprintf("health_%s.json.gz", UTCNow().Format("20060102150405"))
	url += "?filename=" + filename

	_, err := globalSubnetConfig.Upload(url, filename, createHealthJSONGzip(ctx, healthInfo))
	return err
}

Você também pode usar `File()` com `UploadFile`, por exemplo, para definir metadados adicionais:

{* ../../docs_src/request_files/tutorial001_03_an_py39.py hl[9,15] *}

## Uploads de Múltiplos Arquivos

É possível realizar o upload de vários arquivos ao mesmo tempo.

Eles serão associados ao mesmo "campo de formulário" enviado usando "dados de formulário".

Para usar isso, declare uma lista de `bytes` ou `UploadFile`: