/*
 * Copyright 2020 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,

Dans ce cas, le chemin original `/app` serait en réalité servi à `/api/v1/app`.

Même si tout votre code est écrit en supposant qu'il n'y a que `/app`.

{* ../../docs_src/behind_a_proxy/tutorial001_py310.py hl[6] *}

* the fake X
* the HTTP GET method
* the item
* the library
* the lifespan
* the lock
* the middleware
* the mobile application
* the module
* the mounting
* the network
* the origin
* the override
* the payload
* the processor
* the property
* the proxy
* the pull request
* the query
* the RAM
* the remote machine
* the status code
* the string
* the tag

pkg go/types, method (*Interface) IsImplicit() bool
pkg go/types, method (*Interface) IsMethodSet() bool
pkg go/types, method (*Interface) MarkImplicit()
pkg go/types, method (*Named) Origin() *Named
pkg go/types, method (*Named) SetTypeParams([]*TypeParam)
pkg go/types, method (*Named) TypeArgs() *TypeList
pkg go/types, method (*Named) TypeParams() *TypeParamList

/*
 * Copyright 2025 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,

* Se você não entender a pergunta, peça mais **detalhes**.

### Reproduza o problema { #reproduce-the-problem }

Na maioria dos casos e na maioria das perguntas há algo relacionado ao **código original** da pessoa.

Em muitos casos ela só copia um fragmento do código, mas isso não é suficiente para **reproduzir o problema**.

	Versioned bool `msg:"vs"`
}

func (fi FileInfo) shardSize() int64 {
	return ceilFrac(fi.Erasure.BlockSize, int64(fi.Erasure.DataBlocks))
}

// ShardFileSize - returns final erasure size from original size.
func (fi FileInfo) ShardFileSize(totalLength int64) int64 {
	if totalLength == 0 {
		return 0
	}
	if totalLength == -1 {
		return -1
	}
	numShards := totalLength / fi.Erasure.BlockSize

                Object inputLocation)
                implements XmlNode, Serializable {

            private Impl {
                // Validation and normalization from the original constructor
                prefix = prefix == null ? "" : prefix;
                namespaceUri = namespaceUri == null ? "" : namespaceUri;
                name = Objects.requireNonNull(name);

If you catch an exception in a dependency with `yield`, unless you are raising another `HTTPException` or similar, **you should re-raise the original exception**.

You can re-raise the same exception using `raise`:

{* ../../docs_src/dependencies/tutorial008d_an_py310.py hl[17] *}

   * immutable list is returned.)
   *
   * <p><b>Note:</b> in almost all circumstances, the returned {@link ImmutableList} retains a
   * strong reference to {@code this}, which may prevent the original list from being garbage
   * collected. If you want the original list to be eligible for garbage collection, you should
   * create and use a copy of the sub list (e.g., {@code
   * ImmutableList.copyOf(originalList.subList(...))}).
   */
  @Override