* even {@code java.util.HashSet}, and places considerably less load on the garbage collector. Like
 * {@code java.util.LinkedHashSet}, it offers insertion-order iteration, with identical behavior.
 *
 * <p>This class should not be assumed to be universally superior to {@code
 * java.util.LinkedHashSet}. Generally speaking, this class reduces object allocation and memory

   * value that are {@linkplain Range#isConnected connected} to this range.
   *
   * <p>The behavior of {@link #get(Comparable) get(k)} after calling this method is identical to
   * the behavior described in {@link #put(Range, Object) put(range, value)}, however the ranges
   * returned from {@link #asMapOfRanges} will be different if there were existing entries which

          result.throwException();
          return 0; // Not called.
        }
      }
    }
  }

  /** Returns a new CharBuffer identical to buf, except twice the capacity. */
  private static CharBuffer grow(CharBuffer buf) {
    char[] copy = Arrays.copyOf(buf.array(), buf.capacity() * 2);
    CharBuffer bigger = CharBuffer.wrap(copy);

          result.throwException();
          return 0; // Not called.
        }
      }
    }
  }

  /** Returns a new CharBuffer identical to buf, except twice the capacity. */
  private static CharBuffer grow(CharBuffer buf) {
    char[] copy = Arrays.copyOf(buf.array(), buf.capacity() * 2);
    CharBuffer bigger = CharBuffer.wrap(copy);

    }
    int[] stripes = new int[result.size()];
    for (int i = 0; i < result.size(); i++) {
      stripes[i] = indexFor(result.get(i));
    }
    Arrays.sort(stripes);
    // optimize for runs of identical stripes
    int previousStripe = stripes[0];
    result.set(0, getAt(previousStripe));
    for (int i = 1; i < result.size(); i++) {
      int currentStripe = stripes[i];
      if (currentStripe == previousStripe) {

   * 'affect' a bit(j) in the output if two inputs, identical but for bit(i), will differ at output
   * bit(j) about half the time
   *
   * <p>Funneling is pretty simple to detect. The key idea is to find example keys which
   * unequivocally demonstrate that funneling cannot be occurring. This is done bit-by-bit. For each
   * input bit(i) and output bit(j), two pairs of keys must be found with all bits identical except

         * with ours. Therefore, we have to be careful about whether we create our own TypeVariable:
         *
         * 2a. If the resolved types are identical to the original types, then we can return the
         * original, identical JDK TypeVariable. By doing so, we sidestep the problem entirely.
         *
         * 2b. If the resolved types are different from the original types, things are trickier. The

    }

    @Override
    public boolean equals(@CheckForNull Object obj) {
      if (NativeTypeVariableEquals.NATIVE_TYPE_VARIABLE_ONLY) {
        // equal only to our TypeVariable implementation with identical bounds
        if (obj != null
            && Proxy.isProxyClass(obj.getClass())
            && Proxy.getInvocationHandler(obj) instanceof TypeVariableInvocationHandler) {

	if db5.Error != nil {
		t.Errorf("Should not raise error for join where identical fields in different tables. Error: %s", db5.Error.Error())
	}

	var users6 []User
	DB.Joins("inner join pets on pets.user_id = users.id AND pets.name = @Name", user.Pets[0]).Where("users.name = ?", user.Name).First(&users6)

			destBucket:            "destinationbucket",
			sameTarget:            false,
			expectedParsingErr:    nil,
			expectedValidationErr: errDestinationArnMissing,
		},
		// 5 replication destination in different rules not identical
		{