* first permutation will be in ascending order, and the last will be in descending order.
   *
   * <p>Duplicate elements are considered equal. For example, the list [1, 1] will have only one
   * permutation, instead of two. This is why the elements have to implement {@link Comparable}.
   *
   * <p>An empty iterable has only one permutation, which is an empty list.
   *

   * over keys in the order they were first encountered in the input, and the values for each key
   * are iterated in the order they were encountered. If two values for the same key are {@linkplain
   * Object#equals equal}, the first value encountered is used.
   *
   * @throws NullPointerException if any key, value, or entry is null
   * @since 19.0
   */

// Both type and value must match.
func (v Value) Equals(b Value) (ok bool) {
	if !v.SameTypeAs(b) {
		return false
	}
	return reflect.DeepEqual(v.value, b.value)
}

// SameTypeAs return whether the two types are strictly the same.
func (v Value) SameTypeAs(b Value) (ok bool) {
	switch v.value.(type) {
	case bool:
		_, ok = b.value.(bool)
	case string:
		_, ok = b.value.(string)
	case int64:

import java.util.Iterator;
import java.util.Map;
import java.util.NoSuchElementException;
import java.util.Objects;
import java.util.Set;
import org.jspecify.annotations.Nullable;

/**
 * A {@link BiMap} backed by two hash tables. This implementation allows null keys and values. A
 * {@code HashBiMap} and its inverse are both serializable.
 *
 * <p>This implementation guarantees insertion-based iteration order of its keys.
 *

 * href="https://docs.oracle.com/en/java/javase/25/docs/api/java.base/java/lang/Character.html#supplementary">encoded
 * into a {@code String} using surrogate pairs</a>, and a {@code CharMatcher} treats these just as
 * two separate characters. {@link #countIn} counts each supplementary character as 2 {@code char}s.
 *
 * <p>For up-to-date Unicode character properties (digit, letter, etc.) and support for

You must make sure that they, too, receive or can get the source code.
And you must show them these terms so they know their rights.

We protect your rights with two steps: (1) copyright the software, and
(2) offer you this license which gives you legal permission to copy,
distribute and/or modify the software.

Also, for each author's protection and ours, we want to make certain

// healing traversal may be mutating on-disk data when an external
// quit signal is received, this routine cannot quit immediately and
// has to wait until a safe point is reached, such as between scanning
// two objects.
func (h *healSequence) traverseAndHeal(objAPI ObjectLayer) {
	h.traverseAndHealDoneCh <- h.healItems(objAPI)
	xioutil.SafeClose(h.traverseAndHealDoneCh)
}

    return ImmutableList.copyOf(SORTED_NUMBER_NAMES.subList(i, j));
  }

  private static final ImmutableList<String> NUMBER_NAMES =
      ImmutableList.of("one", "two", "three", "four", "five", "six", "seven");

  private static final ImmutableList<String> SORTED_NUMBER_NAMES =
      Ordering.<String>natural().immutableSortedCopy(NUMBER_NAMES);

  public static <E extends @Nullable Object> FluentIterable<E> from(FluentIterable<E> iterable) {
    return checkNotNull(iterable);
  }

  /**
   * Returns a fluent iterable that combines two iterables. The returned iterable has an iterator
   * that traverses the elements in {@code a}, followed by the elements in {@code b}. The source
   * iterators are not polled until necessary.
   *

   *     (arg1, arg2) -> arg1 + ":" + arg2)
   * }
   *
   * <p>will return {@code Stream.of("foo1:bar1", "foo2:bar2")}.
   *
   * <p>The resulting stream will only be as long as the shorter of the two input streams; if one
   * stream is longer, its extra elements will be ignored.
   *
   * <p>Note that if you are calling {@link Stream#forEach} on the resulting stream, you might want