// file. Ideally, we'd do full pattern-evaluation against the sysprops, but this
        // is a first step. There are several replacements below, in order to normalize
        // the path character before we operate on the string as a regex input, and
        // in order to avoid surprises with the File construction...
        // -------------------------------------------------------------------------------------

        }
    ]
}
foo_is_short = {
    "detail": [
        {
            "ctx": {"min_length": 1},
            "loc": ["query", "foo"],
            "msg": "String should have at least 1 character",
            "type": "string_too_short",
            "input": "",
        }
    ]
}


@pytest.mark.parametrize(
    "path,expected_status,expected_response",
    [

      ImmutableSet.of(
          // keep-sorted start
          "\u7f51\u7edc.Cn", // "网络.Cn"
          "co.uk",
          "co.uk.", // Trailing dot
          "co\uFF61uk", // Alternate dot character
          "com",
          "gov.ck",
          "org.ck",
          "org.mK",
          "us",
          // keep-sorted end
          "j\u00f8rpeland.no", // "jorpeland.no" (first o slashed)

    }

    /**
     * Determines the configuration type from a given config ID.
     * The config type is identified by the first character of the config ID.
     *
     * @param configId the configuration ID to analyze
     * @return the ConfigType (WEB, FILE, or DATA) or null if the config ID is invalid or doesn't match any known type
     */

   * ("constant tables"). Example:
   *
   * {@snippet :
   * static final ImmutableTable<Integer, Character, String> SPREADSHEET =
   *     new ImmutableTable.Builder<Integer, Character, String>()
   *         .put(1, 'A', "foo")
   *         .put(1, 'B', "bar")
   *         .put(2, 'A', "baz")
   *         .buildOrThrow();
   * }
   *

        final StringBuilder buf = new StringBuilder(searchWord.length());
        char prev = 0;
        for (final char c : searchWord.toCharArray()) {
            if (!Character.isWhitespace(c)) {
                buf.append(c);
            } else if (!Character.isWhitespace(prev)) {
                buf.append(' ');
            }
            prev = c;
        }
        final String[] words = buf.toString().trim().split(" ");

Sempre que você passa exatamente o mesmo conteúdo (exatamente a mesma senha), você obtém exatamente a mesma sequência aleatória de caracteres.

Mas você não pode converter a sequência aleatória de caracteres de volta para a senha.

##### Porque usar hashing de senha { #why-use-password-hashing }

     */
    Settings read(File input, Map<String, ?> options) throws IOException, SettingsParseException;

    /**
     * Reads the settings from the specified character reader. The reader will be automatically closed before the method
     * returns.
     *
     * @param input The reader to deserialize the settings from, must not be {@code null}.

     */
    PersistedToolchains read(File input, Map<String, ?> options) throws IOException, ToolchainsParseException;

    /**
     * Reads the toolchains from the specified character reader. The reader will be automatically closed before the
     * method returns.
     *
     * @param input The reader to deserialize the toolchains from, must not be {@code null}.

     */
    Metadata read(File input, Map<String, ?> options) throws IOException, MetadataParseException;

    /**
     * Reads the metadata from the specified character reader. The reader will be automatically closed before the method
     * returns.
     *
     * @param input The reader to deserialize the metadata from, must not be {@code null}.