Aktualisieren Sie `get_current_user`, um den gleichen Token wie zuvor zu erhalten, dieses Mal jedoch unter Verwendung von JWT-Tokens.

Dekodieren Sie den empfangenen Token, validieren Sie ihn und geben Sie den aktuellen Benutzer zurück.

Wenn der Token ungültig ist, geben Sie sofort einen HTTP-Fehler zurück.

//// tab | Python 3.10+

```Python hl_lines="89-106"
{!> ../../docs_src/security/tutorial004_an_py310.py!}
```

////

Und es sollte einen `access_token` haben, mit einem String, der unseren Zugriffstoken enthält.

In diesem einfachen Beispiel gehen wir einfach völlig unsicher vor und geben denselben `username` wie der Token zurück.

/// tip | "Tipp"

Im nächsten Kapitel sehen Sie eine wirklich sichere Implementierung mit Passwort-Hashing und <abbr title="JSON Web Tokens">JWT</abbr>-Tokens.

### Conventions

Once a new property has been introduced, you need to consider what its conventions will be.

        return;
      }
      // Otherwise, it's the first time seeing this lock relationship. Look for
      // a path from the acquiredLock to this.
      Set<LockGraphNode> seen = Sets.newIdentityHashSet();
      ExampleStackTrace path = acquiredLock.findPathTo(this, seen);

      if (path == null) {
        // this can be safely acquired after the acquiredLock.
        //

Author: Klaus Post <******@****.***>
Date:   Thu Nov 18 12:15:22 2021 -0800

    Improve performance on multiple versions (#13573)
```

- A fix must be a valid fix that was reproduced and seen in a customer environment, for example.

```
commit 886262e58af77ebc7c836ef587c08544e9a0c271
Author: Harshavardhana <******@****.***>
Date:   Wed Nov 17 15:49:12 2021 -0800

Open Source Code of Conduct
===========================

At Square, we are committed to contributing to the open source community and simplifying the process
of releasing and managing open source software. We’ve seen incredible support and enthusiasm from
thousands of people who have already contributed to our projects — and we want to ensure our community
continues to be truly open for everyone.

    /**
     * <a href="https://en.wikipedia.org/wiki/ANSI_escape_code#Colors">ANSI 8 colors</a> for fluent API
     */
    public enum Color {
        BLACK(0, "BLACK"),
        RED(1, "RED"),
        GREEN(2, "GREEN"),
        YELLOW(3, "YELLOW"),
        BLUE(4, "BLUE"),
        MAGENTA(5, "MAGENTA"),
        CYAN(6, "CYAN"),
        WHITE(7, "WHITE"),
        DEFAULT(9, "DEFAULT");

        private final int value;

     *       thread
     *   <li>If this field's value == null because of unsafe publication, we know that it isn't the
     *       object associated with our thread, because if it was the publication wouldn't have been
     *       unsafe and we'd have seen our thread as the value. This state is also why a new
     *       ThreadConfinedTaskQueue object must be created for each inline execution, because

      for (int insertion = 0; insertion < totalInsertions; insertion++) {
        RandomHasherAction.pickAtRandom(random).performAction(random, sinksAndControl);
      }
      // We need to ensure that at least 4 bytes have been put into the hasher or else
      // Hasher#hash will throw an ISE.
      int intToPut = random.nextInt();
      for (Hasher hasher : sinksAndControl) {
        hasher.putInt(intToPut);
      }

				// Following check is for situations
				// when Writes() scale higher than Reads()
				// - practically speaking this never happens
				// and should never happen - however it has
				// been seen recently due to hardware issues
				// causes Reads() to go slower than Writes().
				//
				// Send such results anyways as this shall
				// expose a problem underneath.
				if totalPut > throughputHighestPut {