* Sets the number of occurrences of {@code element} to {@code newCount}, but only if the count is
   * currently {@code expectedOldCount}. If {@code element} does not appear in the multiset exactly
   * {@code expectedOldCount} times, no changes will be made.
   *
   * @return {@code true} if the change was successful. This usually indicates that the multiset has
   *     been modified, but not always: in the case that {@code expectedOldCount == newCount}, the

   * should use an explicit {@code break} or be certain that you will eventually remove all the
   * elements.
   *
   * <p>To cycle over the iterable {@code n} times, use the following: {@code
   * Iterables.concat(Collections.nCopies(n, iterable))}
   *
   * <p><b>Java 8+ users:</b> The {@code Stream} equivalent of this method is {@code

## Opiniões { #opinions }

"*[...] Estou usando **FastAPI** muito esses dias. [...] Estou na verdade planejando utilizar ele em todos os times de **serviços _Machine Learning_ na Microsoft**. Alguns deles estão sendo integrados no _core_ do produto **Windows** e alguns produtos **Office**.*"

	defer h.mutex.RUnlock()
	// background heal never ends
	if h.clientToken == bgHealingUUID {
		return false
	}
	return !h.endTime.IsZero()
}

// stops the heal sequence - safe to call multiple times.
func (h *healSequence) stop() {
	h.cancelCtx()
}

// pushHealResultItem - pushes a heal result item for consumption in
// the heal-status API. It blocks if there are

     */
    int getNotifyBufferSize();

    /**
     *
     *
     * Property {@code jcifs.smb.client.maxRequestRetries} (int, default 2)
     *
     * @return retry SMB requests on failure up to n times
     */
    int getMaxRequestRetries();

    /**
     * Property {@code jcifs.smb.client.strictResourceLifecycle} (bool, default false)
     *

* Then **comment** saying that you did that, that's how I will know you really checked it.

/// info

Unfortunately, I can't simply trust PRs that just have several approvals.

Several times it has happened that there are PRs with 3, 5 or more approvals, probably because the description is appealing, but when I check the PRs, they are actually broken, have a bug, or don't solve the problem they claim to solve. 😅

   */
  Set<E> outEdges(N node);

  /**
   * Returns the count of {@code node}'s {@link #incidentEdges(Object) incident edges}, counting
   * self-loops twice (equivalently, the number of times an edge touches {@code node}).
   *
   * <p>For directed networks, this is equal to {@code inDegree(node) + outDegree(node)}.
   *

      int same = 0x0; // bitset for output bits with same values
      int diff = 0x0; // bitset for output bits with different values
      int count = 0;
      // originally was 2 * Math.log(...), making it try more times to avoid flakiness issues
      int maxCount = (int) (4 * Math.log(2 * keyBits * hashBits) + 1);
      while (same != 0xffffffff || diff != 0xffffffff) {
        int key1 = rand.nextInt();
        // flip input bit for key2

        totalKeyRotations.incrementAndGet();
        lastKeyRotationTime.set(System.currentTimeMillis());
    }

    /**
     * Get the current key rotation count
     *
     * @return number of times keys have been rotated
     */
    public int getKeyRotationCount() {
        return rotationCount;
    }

    /**
     * Set the key rotation bytes limit
     *

   * nodes. This is an O(n) operation in the common case (and O(n^2) in the worst), but we are saved
   * by two things.
   *
   * <ul>
   *   <li>This is only called when a waiting thread times out or is interrupted. Both of which
   *       should be rare.
   *   <li>The waiters list should be very short.
   * </ul>
   */
  private void removeWaiter(Waiter node) {