* @return whether this is an IP address
     */
    public static boolean isDotQuadIP(final String hostname) {
        if (Character.isDigit(hostname.charAt(0))) {
            int i, len, dots;
            char[] data;

            i = dots = 0; /* quick IP address validation */
            len = hostname.length();
            data = hostname.toCharArray();
            while (i < len && Character.isDigit(data[i++])) {

   * Reader#skip(long) skip} to the end of the stream, and return the total number of chars that
   * were skipped.
   *
   * <p>Note that for sources that implement {@link #lengthIfKnown} to provide a more efficient
   * implementation, it is <i>possible</i> that this method will return a different number of chars
   * than would be returned by reading all of the chars.
   *

   * Reader#skip(long) skip} to the end of the stream, and return the total number of chars that
   * were skipped.
   *
   * <p>Note that for sources that implement {@link #lengthIfKnown} to provide a more efficient
   * implementation, it is <i>possible</i> that this method will return a different number of chars
   * than would be returned by reading all of the chars.
   *

   * <i>might</i> perform better than its longhand equivalent, but should not perform worse. Note
   * that no character encoding is performed; the low byte and high byte of each {@code char} are
   * hashed directly (in that order).
   *
   * <p><b>Warning:</b> This method will produce different output than most other languages do when

      int ch1 = decode(string.charAt(i)) << 4;
      int ch2 = decode(string.charAt(i + 1));
      bytes[i / 2] = (byte) (ch1 + ch2);
    }
    return fromBytesNoCopy(bytes);
  }

  private static int decode(char ch) {
    if (ch >= '0' && ch <= '9') {
      return ch - '0';
    }
    if (ch >= 'a' && ch <= 'f') {
      return ch - 'a' + 10;
    }

   * <i>might</i> perform better than its longhand equivalent, but should not perform worse. Note
   * that no character encoding is performed; the low byte and high byte of each {@code char} are
   * hashed directly (in that order).
   *
   * <p><b>Warning:</b> This method will produce different output than most other languages do when

#
# Default mapping as follows:
# --------------------------------------------------------
# | JDBC Type     | Java Native          | CSharp Native |
# | ------------------------------------------------------
# | CHAR          | java.lang.String     | String        |
# | VARCHAR       | java.lang.String     | String        |
# | LONGVARCHAR   | java.lang.String     | String        |
# | NUMERIC       | java.math.BigDecimal | decimal?      |

            return filename;
        }
        final StringBuilder buf = new StringBuilder(filename.length() + 10);
        for (int i = 0; i < filename.length(); i++) {
            final char c = filename.charAt(i);
            switch (c) {
            case '?':
                buf.append("%3f");
                break;
            case '#':
                buf.append("%23");
                break;

                    nc.setName(this.getUsername() + "@" + userDomain);
                }
            } else if (cb instanceof PasswordCallback pc) {
                char[] passwordChars = this.getPasswordAsCharArray();
                if (passwordChars != null) {
                    pc.setPassword(passwordChars);
                }
            }
        }
    }

            return doNameQuery(new Name(host, type, scope), svr);
        }
        int IP = 0x00;
        int hitDots = 0;
        final char[] data = host.toCharArray();

        for (int i = 0; i < data.length; i++) {
            char c = data[i];
            if (c < 48 || c > 57) {
                return doNameQuery(new Name(host, type, scope), svr);
            }
            int b = 0x00;