@Test fun nonBasicCodePointInInsertionCoding() {
    assertNull(Punycode.decode("xn--cat-ñ3h"))
  }

  @Test fun unterminatedCodePoint() {
    assertNull(Punycode.decode("xn--cat-n"))
  }

  @Test fun overflowI() {
    assertNull(Punycode.decode("xn--99999999"))
  }

  @Test fun overflowMaxCodePoint() {
    assertNull(Punycode.decode("xn--a-b.net"))
    assertNull(Punycode.decode("xn--a-9b.net"))

     * might not run some of its listeners. The likely result is that the app will hang. (And of
     * course stack overflows are bad news in general. For example, we may have overflowed in the
     * middle of defining a class. If so, that class will never be loadable in this process.) The
     * best we can do (since logging may overflow the stack) is to let the error propagate. Because

     * might not run some of its listeners. The likely result is that the app will hang. (And of
     * course stack overflows are bad news in general. For example, we may have overflowed in the
     * middle of defining a class. If so, that class will never be loadable in this process.) The
     * best we can do (since logging may overflow the stack) is to let the error propagate. Because

   * Math#addExact(long, long)}. Also note that adding two {@code int} values can <b>never</b>
   * overflow a {@code long}, so you can just write {@code (long) a + b}.
   *
   * @throws ArithmeticException if {@code a + b} overflows in signed {@code long} arithmetic
   */
  @InlineMe(replacement = "Math.addExact(a, b)")
  public static long checkedAdd(long a, long b) {

'BODY':\n      return element.ownerDocument.body\n    case '#document':\n      return element.body\n  }\n\n  // Firefox want us to check `-x` and `-y` variations as well\n  const { overflow, overflowX, overflowY } = getStyleComputedProperty(element);\n  if (/(auto|scroll|overlay)/.test(overflow + overflowY + overflowX)) {\n    return element;\n  }\n\n  return getScrollParent(getParentNode(element));\n}\n","/**\n * Returns the reference node of the reference object, or the reference object itself.\n...

      long result = origin + distance;
      if (result < 0) {
        checkArgument(origin < 0, "overflow");
      }
      return result;
    }

    @Override
    public long distance(Long start, Long end) {
      long result = end - start;
      if (end > start && result < 0) { // overflow
        return Long.MAX_VALUE;
      }
      if (end < start && result > 0) { // underflow

      long result = origin + distance;
      if (result < 0) {
        checkArgument(origin < 0, "overflow");
      }
      return result;
    }

    @Override
    public long distance(Long start, Long end) {
      long result = end - start;
      if (end > start && result < 0) { // overflow
        return Long.MAX_VALUE;
      }
      if (end < start && result > 0) { // underflow

))||!ce.isEmptyObject(d))for(r in f&&1===e.nodeType&&(n.overflow=[h.overflow,h.overflowX,h.overflowY],null==(l=v&&v.display)&&(l=_.get(e,"display")),"none"===(c=ce.css(e,"display"))&&(l?c=l:(re([e],!0),l=e.style.display||l,c=ce.css(e,"display"),re([e]))),("inline"===c||"inline-block"===c&&null!=l)&&"none"===ce.css(e,"float")&&(u||(p.done(function(){h.display=l}),null==l&&(c=h.display,l="none"===c?"":c)),h.display="inline-block")),n.overflow&&(h.overflow="hidden",p.always(function(){h.overflow=n....

").defaultPrevented)return;const t=this._element.scrollHeight>document.documentElement.clientHeight,e=this._element.style.overflowY;"hidden"===e||this._element.classList.contains(ee)||(t||(this._element.style.overflowY="hidden"),this._element.classList.add(ee),this._queueCallback((()=>{this._element.classList.remove(ee),this._queueCallback((()=>{this._element.style.overflowY=e}),this._dialog)}),this._dialog),this._element.focus())}_adjustDialog(){const t=this._element.scrollHeight>document.docum...

              || !fitsInLong(BigIntegerMath.binomial(LongMath.biggestBinomials[k] + 1, k)));
      // In the first case, any long is valid; in the second, we want to test that the next-bigger
      // long overflows.
    }
    int k = LongMath.biggestBinomials.length;
    assertFalse(fitsInLong(BigIntegerMath.binomial(2 * k, k)));
    // 2 * k is the smallest value for which we don't replace k with (n-k).
  }