peer.acceptFrame() // DATA STREAM 3 "abcde"
    peer.acceptFrame() // HEADERS STREAM 3
    peer.play()

    // Play it back.
    val connection = connect(peer)
    val stream = connection.newStream(headerEntries("a", "android"), true)
    stream.enqueueTrailers(headersOf("foo", "bar"))
    val sink = stream.getSink().buffer()
    sink.writeUtf8("abcdefghi")
    sink.close()

  By the time she had caught the flamingo and brought it back,
the fight was over, and both the hedgehogs were out of sight:
`but it doesn't matter much,' thought Alice, `as all the arches
are gone from this side of the ground.'  So she tucked it away
under her arm, that it might not escape again, and went back for
a little more conversation with her friend.

  When she got back to the Cheshire Cat, she was surprised to

func (S) StructValueMethod()
func (ignored S) StructValueMethodNamedRecv()

func (s *S2) unexported(x int8, y int16, z int64) {}

func Bar(x int8, y int16, z int64)                  {}
func Bar1(x int8, y int16, z int64) uint64          {}
func Bar2(x int8, y int16, z int64) (uint8, uint64) {}
func BarE() Error                                   {}

func unexported(x int8, y int16, z int64) {}

func TakesFunc(f func(dontWantName int) int)

bar...

pkg p1, const FloatConst = 1.5  // 3/2
pkg p1, const FloatConst ideal-float
pkg p1, const StrConst = "foo"
pkg p1, const StrConst ideal-string
pkg p1, func Bar(int8, int16, int64)
pkg p1, func Bar1(int8, int16, int64) uint64
pkg p1, func Bar2(int8, int16, int64) (uint8, uint64)
pkg p1, func BarE() Error
pkg p1, func Now() Time
pkg p1, func PlainFunc(int, int, string) (*B, error)
pkg p1, func TakesFunc(func(int) int)
pkg p1, method (*B) JustOnB()

   *
   * <p>For example:
   *
   * <pre>{@code
   * Streams.zip(
   *   Stream.of("foo1", "foo2", "foo3"),
   *   Stream.of("bar1", "bar2"),
   *   (arg1, arg2) -> arg1 + ":" + arg2)
   * }</pre>
   *
   * <p>will return {@code Stream.of("foo1:bar1", "foo2:bar2")}.
   *
   * <p>The resulting stream will only be as long as the shorter of the two input streams; if one

   *
   * <p>For example:
   *
   * <pre>{@code
   * Streams.zip(
   *   Stream.of("foo1", "foo2", "foo3"),
   *   Stream.of("bar1", "bar2"),
   *   (arg1, arg2) -> arg1 + ":" + arg2)
   * }</pre>
   *
   * <p>will return {@code Stream.of("foo1:bar1", "foo2:bar2")}.
   *
   * <p>The resulting stream will only be as long as the shorter of the two input streams; if one

For a more "real life" example of this, imagine a bank.

Up to recently, most of the banks had multiple cashiers 👨‍💼👨‍💼👨‍💼👨‍💼 and a big line 🕙🕙🕙🕙🕙🕙🕙🕙.

All of the cashiers doing all the work with one client after the other 👨‍💼⏯.

And you have to wait 🕙 in the line for a long time or you lose your turn.

You probably wouldn't want to take your crush 😍 with you to run errands at the bank 🏦.

### Burger Conclusion

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a:focus,.navbar-light .navbar-text a:hover{color:rgba(0,0,0,.9)}.navbar-dark .navbar-brand{color:#fff}.navbar-dark .navbar-brand:focus,.navbar-dark .navbar-brand:hover{color:#fff}.navbar-dark .navbar-nav .nav-link{color:rgba(255,255,255,.75)}.navbar-dark .navbar-nav .nav-link:focus,.navbar-dark .navbar-nav .nav-link:hover{color:#fff}.navbar-dark .navbar-nav .nav-link.disabled{color:rgba(255,255,255,.25)}.navbar-dark .navbar-nav .active>.nav-link,.navbar-dark .navbar-nav .nav-link.active,.navbar-dark .navbar-nav ...