`tf.divide()` is now the recommended division function. `tf.div()` will remain,
but its semantics do not respond to Python 3 or `from future` mechanisms. *
tf.reverse() now takes indices of axes to be reversed. E.g. `tf.reverse(a,
[True, False, True])` must now be written as `tf.reverse(a, [0, 2])`.
`tf.reverse_v2()` will remain until 1.0 final. * `tf.mul`, `tf.sub` and `tf.neg`

* Added DNS Reverse Record logic for service IPs ([#26226](https://github.com/kubernetes/kubernetes/pull/26226), [@ArtfulCoder](https://github.com/ArtfulCoder))

2034          ; mapped                 ; 2032 2032 2032 #1.1  TRIPLE PRIME
2035          ; valid                  ;      ; NV8    # 1.1  REVERSED PRIME
2036          ; mapped                 ; 2035 2035     # 1.1  REVERSED DOUBLE PRIME
2037          ; mapped                 ; 2035 2035 2035 #1.1  REVERSED TRIPLE PRIME
2038..203B    ; valid                  ;      ; NV8    # 1.1  CARET..REFERENCE MARK

      Entry<V, K> reversed = reverseEntry(entry);
      BiMap<V, K> inv = getMap().inverse();
      assertFalse(
          "Inverse should not contain entry " + reversed, inv.entrySet().contains(reversed));
      assertFalse(
          "Inverse should not contain key " + reversed.getKey(),
          inv.containsKey(reversed.getKey()));
      assertFalse(
          "Inverse should not contain value " + reversed.getValue(),

    assertThat(newFirst.getHash()).isEqualTo(hashThree);
    assertThat(newFirst.getNext()).isSameInstanceAs(entryOne);

    // tail (remaining entries are copied in reverse order)
    newFirst = segment.removeEntryFromChain(entryThree, entryOne);
    assertThat(newFirst.getKey()).isSameInstanceAs(keyTwo);
    assertThat(newFirst.getValueReference().get()).isSameInstanceAs(valueTwo);

    assertThat(newFirst.getHash()).isEqualTo(hashThree);
    assertThat(newFirst.getNext()).isSameInstanceAs(entryOne);

    // tail (remaining entries are copied in reverse order)
    newFirst = segment.removeEntryFromChain(entryThree, entryOne);
    assertThat(newFirst.getKey()).isSameInstanceAs(keyTwo);
    assertThat(newFirst.getValueReference().get()).isSameInstanceAs(valueTwo);

      Entry<V, K> reversed = reverseEntry(entry);
      BiMap<V, K> inv = getMap().inverse();
      assertFalse(
          "Inverse should not contain entry " + reversed, inv.entrySet().contains(reversed));
      assertFalse(
          "Inverse should not contain key " + reversed.getKey(),
          inv.containsKey(reversed.getKey()));
      assertFalse(
          "Inverse should not contain value " + reversed.getValue(),

static boolean isAlphanumericSpace(String); public static boolean isNumeric(String); public static boolean isNumericSpace(String); public static String defaultString(Object); public static String defaultString(Object, String); public static String reverse(String); public static String reverseDelimitedStri(String, String); private static void reverseArray(Object[]); public static String abbreviate(String, int); public static String abbreviate(String, int, int); public static String difference(String,...

    final HashBiMap<K, V> obverse;

    Inverse(HashBiMap<K, V> obverse) {
      this.obverse = obverse;
    }

    @Override
    public int size() {
      return obverse.size;
    }

    @Override
    public boolean containsKey(@Nullable Object key) {
      Object obverseValue = key;
      return obverse.containsValue(obverseValue);
    }

    @Override

  /**
   * Returns the inverse view of this bimap, which maps each of this bimap's values to its
   * associated key. The two bimaps are backed by the same data; any changes to one will appear in
   * the other.
   *
   * <p><b>Note:</b> There is no guaranteed correspondence between the iteration order of a bimap
   * and that of its inverse.
   *
   * @return the inverse view of this bimap
   */