* terms</a>):
 *
 * <ul>
 *   <li>directed graphs
 *   <li>undirected graphs
 *   <li>graphs that do/don't allow self-loops
 *   <li>graphs whose nodes/edges are insertion-ordered, sorted, or unordered
 * </ul>
 *
 * <p>{@code Graph} explicitly does not support parallel edges, and forbids implementations or
 * extensions with parallel edges. If you need parallel edges, use {@link Network}.
 *

    }
  }

  @SuppressWarnings("unchecked") // this method may throw CCE
  static int compareOrThrow(Comparable left, Comparable right) {
    return left.compareTo(right);
  }

  /** Needed to serialize sorted collections of Ranges. */
  private static class RangeLexOrdering extends Ordering<Range<?>> implements Serializable {
    static final Ordering<?> INSTANCE = new RangeLexOrdering();

    @Override

			fi.Parts[i] = partInfo
			return
		}
	}

	// Proceed to include new part info.
	fi.Parts = append(fi.Parts, partInfo)

	// Parts in FileInfo should be in sorted order by part number.
	sort.Slice(fi.Parts, func(i, j int) bool { return fi.Parts[i].Number < fi.Parts[j].Number })
}

// ObjectToPartOffset - translate offset of an object to offset of its individual part.

  }

  public void testVerifyMegaStreamHalves() {
    assertThat(
            concat(megaPrimitiveDoubleStreamPart1(), megaPrimitiveDoubleStreamPart2())
                .sorted()
                .toArray())
        .isEqualTo(megaPrimitiveDoubleStream().toArray());
  }

  public void testAddAllPrimitiveDoubleStream() {
    StatsAccumulator accumulator = new StatsAccumulator();

     * Returns the index that {@code actualLastElement} now resides in.
     *
     * <p>Since the last element of the array is actually in the middle of the sorted structure, a
     * childless aunt node could be smaller, which would corrupt the invariant if this element
     * becomes the new parent of the aunt node. In that case, we first switch the last element with

        final String permissionKey = userBean.map(user -> StreamUtil.stream(user.getPermissions())
                .get(stream -> stream.sorted().distinct().collect(Collectors.joining("\n")))).orElse(StringUtil.EMPTY);

        try {
            return facetCache.get(query + "\n" + permissionKey, () -> {

    }
  }

  @SuppressWarnings("unchecked") // this method may throw CCE
  static int compareOrThrow(Comparable left, Comparable right) {
    return left.compareTo(right);
  }

  /** Needed to serialize sorted collections of Ranges. */
  private static class RangeLexOrdering extends Ordering<Range<?>> implements Serializable {
    static final Ordering<?> INSTANCE = new RangeLexOrdering();

    @Override

}

// sortByModTime will sort versions by modtime in descending order,
// meaning index 0 will be latest version.
func (x *xlMetaV2) sortByModTime() {
	// Quick check
	if len(x.versions) <= 1 || sort.SliceIsSorted(x.versions, func(i, j int) bool {
		return x.versions[i].header.sortsBefore(x.versions[j].header)
	}) {
		return
	}

	// We should sort.
	sort.Slice(x.versions, func(i, j int) bool {

     * Returns the index that {@code actualLastElement} now resides in.
     *
     * <p>Since the last element of the array is actually in the middle of the sorted structure, a
     * childless aunt node could be smaller, which would corrupt the invariant if this element
     * becomes the new parent of the aunt node. In that case, we first switch the last element with

		bytes.Index(buf.Bytes(), []byte("baz=baz")),
		bytes.Index(buf.Bytes(), []byte("foo=foo")),
		bytes.Index(buf.Bytes(), []byte("qux=qux")),
	}
	if !slices.IsSorted(indices) {
		t.Fatal("PAX headers are not sorted")
	}
}

func TestUSTARLongName(t *testing.T) {
	// Create an archive with a path that failed to split with USTAR extension in previous versions.