var pkgRE = /^[a-z0-9_\/]+$/;

function urlForInput(t) {
    if (!t) {
        return null;
    }

    if (numericRE.test(t)) {
        if (t < 150000) {
            // We could use the golang.org/cl/ handler here, but
            // avoid some redirect latency and go right there, since
            // one is easy. (no server-side mapping)
            return "https://github.com/golang/go/issues/" + t;

        stale-issue-message: "This issue has been marked as invalid question, please give more information by following the `Question` template, if you believe there is a bug of GORM, please create a pull request that could reproduce the issue on [https://github.com/go-gorm/playground](https://github.com/go-gorm/playground), the issue will be closed in 30 days if no further activity occurs. most likely your question already answered https://github.com/go-gorm/gorm/issues...

            File file = null;
            try {
                file = new File(new URI(filePath));
            } catch (final URISyntaxException e) {
                logger.warn("Could not parse url: " + filePath, e);
            }

            if (file == null) {
                responseData.setHttpStatusCode(Constants.NOT_FOUND_STATUS_CODE);
                responseData.setCharSet(charset);

   * to stop requests. You could poll for lifecycle changes in a work loop:
   *
   * <pre>
   *   public void run() {
   *     while ({@link #isRunning()}) {
   *       // perform a unit of work
   *     }
   *   }
   * </pre>
   *
   * <p>...or you could respond to stop requests by implementing {@link #triggerShutdown()}, which

```Python hl_lines="10-12"
{!../../docs_src/response_headers/tutorial001.py!}
```

/// note | "Technical Details"

You could also use `from starlette.responses import Response` or `from starlette.responses import JSONResponse`.

                is.setEncoding(responseData.getCharSet());
            }
            parser.parse(is);
        } catch (final Exception e) {
            throw new CrawlingAccessException("Could not parse " + responseData.getUrl(), e);
        }

        final Document document = parser.getDocument();

        processMetaRobots(responseData, resultData, document);

    private final String lifecycleId;

    /**
     * Creates a new exception to indicate that the specified lifecycle is unknown.
     *
     * @param lifecycleId The identifier of the lifecycle that could not be located, may be {@code null}.
     */
    public LifecycleNotFoundException(String lifecycleId) {
        super("Unknown lifecycle " + lifecycleId);
        this.lifecycleId = (lifecycleId != null) ? lifecycleId : "";

		repairLog.Info("CNI repair controller is disabled")
		return
	}
	repairLog.Info("starting CNI sidecar repair controller")

	client, err := clientSetup()
	if err != nil {
		repairLog.Fatalf("CNI repair could not construct clientSet: %s", err)
	}

	rc, err := NewRepairController(client, cfg)
	if err != nil {
		repairLog.Fatalf("Fatal error constructing repair controller: %+v", err)
	}
	go rc.Run(ctx.Done())

        } catch (final Exception e) {
            CloseableUtil.closeQuietly(fos); // for deleting file
            FileUtil.deleteInBackground(tempFile); // clean up
            throw new CrawlingAccessException("Could not read a response body: " + responseData.getUrl(), e);
        } finally {
            CloseableUtil.closeQuietly(fos);
        }
        return tempFile;
    }

You could have turns as in the burgers example, first the living room, then the kitchen, but as you are not waiting 🕙 for anything, just cleaning and cleaning, the turns wouldn't affect anything.

It would take the same amount of time to finish with or without turns (concurrency) and you would have done the same amount of work.