Ahora, veamos cómo podrías usar eso para devolver un response personalizado.

Digamos que quieres devolver un response en [XML](https://en.wikipedia.org/wiki/XML).

Podrías poner tu contenido XML en un string, poner eso en un `Response`, y devolverlo:

{* ../../docs_src/response_directly/tutorial002_py310.py hl[1,18] *}

 * string {@code "Foo<Bar>"}.
 *
 * <p><b>Note:</b> This class is similar to {@link CharEscaper} but with one very important
 * difference. A CharEscaper can only process Java <a
 * href="http://en.wikipedia.org/wiki/UTF-16">UTF16</a> characters in isolation and may not cope
 * when it encounters surrogate pairs. This class facilitates the correct escaping of all Unicode
 * characters.
 *

To check the 2-letter code for the language you want to translate, you can use the table [List of ISO 639-1 codes](https://en.wikipedia.org/wiki/List_of_ISO_639-1_codes).

#### Request a New Language

Let's say that you want to request translations for a language that is not yet translated, not even some pages. For example, Latin.

* Есть **расширение** протокола **TLS** (того самого, что занимается шифрованием на уровне TCP, до HTTP) под названием **[<abbr title="Server Name Indication - Указание имени сервера">SNI</abbr>](https://en.wikipedia.org/wiki/Server_Name_Indication)**.
    * Это расширение SNI позволяет одному серверу (с **одним IP-адресом**) иметь **несколько HTTPS-сертификатов** и обслуживать **несколько HTTPS-доменов/приложений**.

Voyons maintenant comment vous pourriez utiliser cela pour renvoyer une réponse personnalisée.

Disons que vous voulez renvoyer une [réponse XML](https://en.wikipedia.org/wiki/XML).

Vous pouvez placer votre contenu XML dans une chaîne de caractères, le mettre dans une `Response` et le renvoyer :

{* ../../docs_src/response_directly/tutorial002_py310.py hl[1,18] *}

    * Ancak bunun bir **çözümü** vardır.
* **TLS** protokolüne (TCP seviyesinde, HTTP’den önce şifrelemeyi yapan) eklenen **[<abbr title="Server Name Indication - Sunucu Adı Belirtimi">SNI</abbr>](https://en.wikipedia.org/wiki/Server_Name_Indication)** adlı bir **extension** vardır.

/**
 * A sorted map which forwards all its method calls to another sorted map. Subclasses should
 * override one or more methods to modify the behavior of the backing sorted map as desired per the
 * <a href="http://en.wikipedia.org/wiki/Decorator_pattern">decorator pattern</a>.
 *
 * <p><b>Warning:</b> The methods of {@code ForwardingSortedMap} forward <i>indiscriminately</i> to

/**
 * A list which forwards all its method calls to another list. Subclasses should override one or
 * more methods to modify the behavior of the backing list as desired per the <a
 * href="http://en.wikipedia.org/wiki/Decorator_pattern">decorator pattern</a>.
 *
 * <p>This class does not implement {@link java.util.RandomAccess}. If the delegate supports random

/**
 * A sorted multiset which forwards all its method calls to another sorted multiset. Subclasses
 * should override one or more methods to modify the behavior of the backing multiset as desired per
 * the <a href="http://en.wikipedia.org/wiki/Decorator_pattern">decorator pattern</a>.
 *
 * <p><b>Warning:</b> The methods of {@code ForwardingSortedMultiset} forward
 * <b>indiscriminately</b> to the methods of the delegate. For example, overriding {@link

위 예제는 필요한 모든 부분을 보여주지만, 아직은 그다지 유용하지 않습니다. `item`을 그냥 직접 반환했어도 **FastAPI**가 기본으로 이를 `JSONResponse`에 넣고 `dict`로 변환하는 등의 작업을 모두 수행해 주었을 것이기 때문입니다.

이제, 이를 사용해 사용자 정의 응답을 반환하는 방법을 알아보겠습니다.

예를 들어 [XML](https://en.wikipedia.org/wiki/XML) 응답을 반환하고 싶다고 가정해 보겠습니다.

XML 내용을 문자열에 넣고, 이를 `Response`에 넣어 반환할 수 있습니다:

{* ../../docs_src/response_directly/tutorial002_py310.py hl[1,18] *}

## 응답 모델 동작 방식 { #how-a-response-model-works }