assertThat(Floats.join(",", 1.0f, 2.0f)).isEqualTo("1.0,2.0");
    assertThat(Floats.join("", 1.0f, 2.0f, 3.0f)).isEqualTo("1.02.03.0");
  }

  public void testLexicographicalComparator() {
    List<float[]> ordered =
        Arrays.asList(
            new float[] {},
            new float[] {LEAST},
            new float[] {LEAST, LEAST},
            new float[] {LEAST, 1.0f},
            new float[] {1.0f},

    assertThat(Ints.join(",", (int) 1, (int) 2)).isEqualTo("1,2");
    assertThat(Ints.join("", (int) 1, (int) 2, (int) 3)).isEqualTo("123");
  }

  public void testLexicographicalComparator() {
    List<int[]> ordered =
        Arrays.asList(
            new int[] {},
            new int[] {LEAST},
            new int[] {LEAST, LEAST},
            new int[] {LEAST, (int) 1},
            new int[] {(int) 1},

    assertThat(Floats.join(",", 1.0f, 2.0f)).isEqualTo("1.0,2.0");
    assertThat(Floats.join("", 1.0f, 2.0f, 3.0f)).isEqualTo("1.02.03.0");
  }

  public void testLexicographicalComparator() {
    List<float[]> ordered =
        Arrays.asList(
            new float[] {},
            new float[] {LEAST},
            new float[] {LEAST, LEAST},
            new float[] {LEAST, 1.0f},
            new float[] {1.0f},

    void checkAcquiredLock(Policy policy, LockGraphNode acquiredLock) {
      // checkAcquiredLock() should never be invoked by a lock that has already
      // been acquired. For unordered locks, aboutToAcquire() ensures this by
      // checking isAcquiredByCurrentThread(). For ordered locks, however, this
      // can happen because multiple locks may share the same LockGraphNode. In
      // this situation, throw an IllegalStateException as defined by contract

 *       how the collection was created. Typically this is insertion order unless an explicit
 *       ordering is otherwise specified (e.g. {@link ImmutableSortedSet#naturalOrder}). See the
 *       appropriate factory method for details. View collections such as {@link
 *       ImmutableMultiset#elementSet} iterate in the same order as the parent, except as noted.

		return globalVeeamForceSC
	}
	return s
}

type ordered interface {
	~int | ~int8 | ~int16 | ~int32 | ~int64 | ~uint | ~uint8 | ~uint16 | ~uint32 | ~uint64 | ~uintptr | ~float32 | ~float64 | string
}

// mapKeysSorted returns the map keys as a sorted slice.
func mapKeysSorted[Map ~map[K]V, K ordered, V any](m Map) []K {
	res := make([]K, 0, len(m))
	for k := range m {

	// Otherwise same set of buckets get scanned across erasure sets always.
	// at any given point in time. This allows different buckets to be scanned
	// in different order per erasure set, this wider spread is needed when
	// there are lots of buckets with different order of objects in them.
	r := rand.New(rand.NewSource(time.Now().UnixNano()))
	permutes := r.Perm(len(buckets))
	// Add new buckets first
	for _, idx := range permutes {

    return new ImmutableLongArray(new long[] {e0});
  }

  /** Returns an immutable array containing the given values, in order. */
  public static ImmutableLongArray of(long e0, long e1) {
    return new ImmutableLongArray(new long[] {e0, e1});
  }

  /** Returns an immutable array containing the given values, in order. */
  public static ImmutableLongArray of(long e0, long e1, long e2) {

    return new ImmutableIntArray(new int[] {e0});
  }

  /** Returns an immutable array containing the given values, in order. */
  public static ImmutableIntArray of(int e0, int e1) {
    return new ImmutableIntArray(new int[] {e0, e1});
  }

  /** Returns an immutable array containing the given values, in order. */
  public static ImmutableIntArray of(int e0, int e1, int e2) {
    return new ImmutableIntArray(new int[] {e0, e1, e2});

    }

    return new TransposedNetwork<>(network);
  }

  static <N> EndpointPair<N> transpose(EndpointPair<N> endpoints) {
    if (endpoints.isOrdered()) {
      return EndpointPair.ordered(endpoints.target(), endpoints.source());
    }
    return endpoints;
  }

  // NOTE: this should work as long as the delegate graph's implementation of edges() (like that of