* represent the same element and count. That is, two entries {@code a} and {@code b} are equal
     * if:
     *
     * {@snippet :
     * Objects.equals(a.getElement(), b.getElement())
     *     && a.getCount() == b.getCount()
     * }
     */
    @Override
    // TODO(kevinb): check this wrt TreeMultiset?
    boolean equals(@Nullable Object o);

    /**
     * {@inheritDoc}
     *

   * their map views, as returned by {@link #asMap}, are also equal.
   *
   * <p>In general, two multimaps with identical key-value mappings may or may not be equal,
   * depending on the implementation. For example, two {@link SetMultimap} instances with the same
   * key-value mappings are equal, but equality of two {@link ListMultimap} instances depends on the

    }

    /**
     * Returns whether two strings are equal. If both are null, returns <code>true</code>.
     *
     * @param target1
     *            the first string
     * @param target2
     *            the second string
     * @return true if the strings are equal, false otherwise
     */
    public static boolean equals(final String target1, final String target2) {

      if (method.getReturnType().equals(HashFunction.class) // must return HashFunction
          && Modifier.isPublic(method.getModifiers()) // only the public methods
          && method.getParameterTypes().length != 0 // only the seeded hash functions
          && !method.getName().equals("concatenating") // don't test Hashing.concatenating()
          && !method.getName().equals("goodFastHash") // tested in testGoodFastHashEquals

  }

  /**
   * Returns the {@code int} value that, when treated as unsigned, is equal to {@code value}, if
   * possible.
   *
   * @param value a value between 0 and 2<sup>32</sup>-1 inclusive
   * @return the {@code int} value that, when treated as unsigned, equals {@code value}
   * @throws IllegalArgumentException if {@code value} is negative or greater than or equal to
   *     2<sup>32</sup>
   * @since 21.0
   */

   * be declared as a {@code List}.
   *
   * <p>Note also that serialization is not in general required to return an object that is
   * {@linkplain Object#equals equal} to the original, nor is it required to return even an object
   * of the same class. For example, if sublists of {@code MyList} instances were serializable,

     * represent the same element and count. That is, two entries {@code a} and {@code b} are equal
     * if:
     *
     * {@snippet :
     * Objects.equals(a.getElement(), b.getElement())
     *     && a.getCount() == b.getCount()
     * }
     */
    @Override
    // TODO(kevinb): check this wrt TreeMultiset?
    boolean equals(@Nullable Object o);

    /**
     * {@inheritDoc}
     *

                    }
                }
            } else {
                final Node idAttr = node.getAttributes().getNamedItem("id");
                if (idAttr != null) {
                    final String value = idAttr.getNodeValue();
                    return id.equals(value);
                }
            }
        }
        return false;

        // Act
        MIEName parsed = new MIEName(buf);

        // Assert
        // equals should match case-insensitively for name and equal OID
        MIEName expected = new MIEName(testOid(), name);
        assertEquals(expected, parsed, "Parsed object should equal expected");
        assertEquals(name, parsed.toString(), "toString should return the name");

   * identical inputs: This sounds like it ought to be a problem here, since the goals of this class
   * include testing that {@code equals()} is reflexive and is tolerant of {@code null}. However,
   * there's no problem. The reason: {@link EqualsTester} tests {@code null} and identical inputs
   * directly against {@code equals()} rather than through the {@code Equivalence}.
   */
  private final Equivalence<? super T> equivalence;