}

    @Override
    public E[] createArray(int length) {
      return gen.createArray(length);
    }

    @Override
    public Iterable<E> order(List<E> insertionOrder) {
      return gen.order(insertionOrder);
    }
  }

  private static Set<Feature<?>> computeReserializedCollectionFeatures(Set<Feature<?>> features) {
    Set<Feature<?>> derivedFeatures = new HashSet<>(features);

      }

      @Override
      public List<String> order(List<String> insertionOrder) {
        List<String> order = new ArrayList<>();
        for (String s : insertionOrder) {
          int index = order.indexOf(s);
          if (index == -1) {
            order.add(s);
          } else {
            order.add(index, s);
          }
        }
        return order;
      }
    };
  }

  /*
   * While the current implementation returns `this`, that's not something we mean to guarantee.
   * Callers of TestContainerGenerator.order need to be prepared for implementations to return a new
   * collection.
   */
  @SuppressWarnings("CanIgnoreReturnValueSuggester")
  @Override
  public List<String> order(List<String> insertionOrder) {
    sort(insertionOrder);
    return insertionOrder;
  }

  @Override

  /*
   * While the current implementation returns `this`, that's not something we mean to guarantee.
   * Callers of TestContainerGenerator.order need to be prepared for implementations to return a new
   * collection.
   */
  @SuppressWarnings("CanIgnoreReturnValueSuggester")
  @Override
  public List<AnEnum> order(List<AnEnum> insertionOrder) {
    sort(insertionOrder);
    return insertionOrder;
  }

   * Generation, described in Knuth's "The Art of Computer Programming", Volume 4, Chapter 7,
   * Section 7.2.1.2. The iteration order follows the lexicographical order. This means that the
   * first permutation will be in ascending order, and the last will be in descending order.
   *
   * <p>Duplicate elements are considered equal. For example, the list [1, 1] will have only one

                  public List<String> order(List<String> insertionOrder) {
                    List<String> order = new ArrayList<>();
                    for (String s : insertionOrder) {
                      int index = order.indexOf(s);
                      if (index == -1) {
                        order.add(s);
                      } else {
                        order.add(index, s);
                      }

------------------

Get working code on a personal branch with tests passing before you submit a PR:

```
./gradlew clean check
```

Please make every effort to follow existing conventions and style in order to keep the code as
readable as possible.

Contribute code changes through GitHub by forking the repository and sending a pull request. We
squash all pull requests on merge.


Gradle Setup
------------

```

------------------

Get working code on a personal branch with tests passing before you submit a PR:

```
./gradlew clean check
```

Please make every effort to follow existing conventions and style in order to keep the code as
readable as possible.

Contribute code changes through GitHub by forking the repository and sending a pull request. We
squash all pull requests on merge.


Gradle Setup
------------

```

 * keys and values. The iteration order is preserved across non-distinct key values. For example,
 * for the following multimap definition:
 *
 * {@snippet :
 * Multimap<K, V> multimap = LinkedListMultimap.create();
 * multimap.put(key1, foo);
 * multimap.put(key2, bar);
 * multimap.put(key1, baz);
 * }
 *

    bus.register(processor);

    EventRecorder recorder = new EventRecorder();
    bus.register(recorder);

    bus.post(FIRST);

    assertEquals(
        "EventRecorder expected events in order",
        Lists.<Object>newArrayList(FIRST, SECOND),
        recorder.eventsReceived);
  }

  public class EventProcessor {
    @Subscribe
    public void listenForStrings(String event) {
      bus.post(SECOND);