claim_prefix  (string)    JWT claim namespace prefix e.g. "customer1/"
scopes        (csv)       Comma separated list of OpenID scopes for server, defaults to advertised scopes from discovery document e.g. "email,admin"
comment       (sentence)  optionally add a comment to this setting
```

and ENV based options

```
mc admin config set myminio/ identity_openid --env

KEY:

./mc idp openid add myminio \
	config_url="http://localhost:5556/dex/.well-known/openid-configuration" \
	client_id="minio-client-app" \
	client_secret="minio-client-app-secret" \
	scopes="openid,groups,email,profile" \
	redirect_uri="http://127.0.0.1:10000/oauth_callback" \
	display_name="Login via dex1" \
	role_policy="consoleAdmin"

./mc admin service restart myminio --json
./mc ready myminio

    assert response.status_code == 200, response.text
    assert response.json() == {
        "username": "johndoe",
        "full_name": "John Doe",
        "email": "******@****.***",
        "hashed_password": "fakehashedsecret",
        "disabled": False,
    }


def test_incorrect_token(client: TestClient):

# A static list of passwords to login the end user. By identifying here, dex
# won't look in its underlying storage for passwords.
#
# If this option isn't chosen users may be added through the gRPC API.
staticPasswords:
  - email: "******@****.***"
    # bcrypt hash of the string "password"
    hash: "$2a$10$2b2cU8CPhOTaGrs1HRQuAueS7JTT5ZHsHSzYiFPm1leZck7Mc8T4W"
    username: "admin"

Но вы не ограничены использованием какой-то конкретной модели данных, класса или типа.

Хотите, чтобы в модели были `id` и `email`, но не было `username`? Пожалуйста. Можно использовать те же инструменты.

Хотите просто `str`? Или просто `dict`? Или напрямую экземпляр класса модели базы данных? Всё работает одинаково.

                "Expected merged artifactId to be TARGET but was " + merged.getArtifactId());
    }

    @Test
    void mergeSameContributors() {
        Contributor contributor =
                Contributor.newBuilder().email("******@****.***").build();

        Model target =
                Model.newBuilder().contributors(Arrays.asList(contributor)).build();

        Model source =

Gradle uses pull requests for contributions. Fork [gradle/gradle](https://github.com/gradle/gradle) and clone your fork. Configure your Git username and email with:

    git config user.name 'First Last'
    git config user.email ******@****.***

### IntelliJ IDEA

#### Import Gradle into IntelliJ

To import Gradle into IntelliJ:

			Optional:    true,
			Type:        "string",
		},
		config.HelpKV{
			Key:         Scopes,
			Description: `Comma separated list of OpenID scopes for server, defaults to advertised scopes from discovery document e.g. "email,admin"` + defaultHelpPostfix(Scopes),
			Optional:    true,
			Type:        "csv",
		},
		config.HelpKV{
			Key:         Vendor,

想了解更多，请查阅 <a href="https://fastapi.tiangolo.com/zh/benchmarks/" class="internal-link" target="_blank">基准测试</a> 章节。

## 可选依赖

用于 Pydantic：

* <a href="https://github.com/JoshData/python-email-validator" target="_blank"><code>email-validator</code></a> - 用于 email 校验。

用于 Starlette：

* <a href="https://www.python-httpx.org" target="_blank"><code>httpx</code></a> - 使用 `TestClient` 时安装。

And you can use any model or data for the security requirements (in this case, a Pydantic model `User`).

But you are not restricted to using some specific data model, class or type.

Do you want to have an `id` and `email` and not have any `username` in your model? Sure. You can use these same tools.

Do you want to just have a `str`? Or just a `dict`? Or a database class model instance directly? It all works the same way.