// and include err.Num = s.
//
// If s is not syntactically well-formed, ParseComplex returns err.Err = ErrSyntax.
//
// If s is syntactically well-formed but either component is more than 1/2 ULP
// away from the largest floating point number of the given component's size,
// ParseComplex returns err.Err = ErrRange and c = ±Inf for the respective component.
func ParseComplex(s string, bitSize int) (complex128, error) {
	size := 64

// It is not guaranteed to return the largest such n.
func (f Form) QuickSpan(b []byte) int {
	n, _ := formTable[f].quickSpan(inputBytes(b), 0, len(b), true)
	return n
}

// Span implements transform.SpanningTransformer. It returns a boundary n such
// that b[0:n] == f(b[0:n]). It is not guaranteed to return the largest such n.
func (f Form) Span(b []byte, atEOF bool) (n int, err error) {

	if first > last {
		return &biasedSparseMap{first: math.MaxInt32, s: nil}
	}
	return &biasedSparseMap{first: first, s: newSparseMap(1 + last - first)}
}

// cap returns one more than the largest key valid for s
func (s *biasedSparseMap) cap() int {
	if s == nil || s.s == nil {
		return 0
	}
	return s.s.cap() + int(s.first)
}

// size returns the number of entries stored in s

	return j, z * PI4
}

// mPi4 is the binary digits of 4/pi as a uint64 array,
// that is, 4/pi = Sum mPi4[i]*2^(-64*i)
// 19 64-bit digits and the leading one bit give 1217 bits
// of precision to handle the largest possible float64 exponent.
var mPi4 = [...]uint64{
	0x0000000000000001,
	0x45f306dc9c882a53,
	0xf84eafa3ea69bb81,
	0xb6c52b3278872083,
	0xfca2c757bd778ac3,
	0x6e48dc74849ba5c0,
	0x0c925dd413a32439,

	return resource.ParseQuantity(pageSize)
}

// HugePageUnitSizeFromByteSize returns hugepage size has the format.
// `size` must be guaranteed to divisible into the largest units that can be expressed.
// <size><unit-prefix>B (1024 = "1KB", 1048576 = "1MB", etc).
func HugePageUnitSizeFromByteSize(size int64) (string, error) {

		// the lowest bucket was based around the 180ns/op figure for BenchmarkAccess,
		// plus some additional leeway to account for the apiserver doing other things
		// the largest bucket was chosen based on the fact that benchmarks indicate the
		// same Xeon running a CEL expression close to the estimated cost limit takes
		// around 760ms, so that bucket should only ever have the slowest CEL expressions

#include <sys/cpuset.h>
#include <sys/param.h>
#include <sys/vdso.h>
*/
import "C"

// Local consts.
const (
	_NBBY            = C.NBBY            // Number of bits in a byte.
	_CTL_MAXNAME     = C.CTL_MAXNAME     // Largest number of components supported.
	_CPU_LEVEL_WHICH = C.CPU_LEVEL_WHICH // Actual mask/id for which.
	_CPU_WHICH_PID   = C.CPU_WHICH_PID   // Specifies a process id.
)

const (
	EINTR     = C.EINTR
	EFAULT    = C.EFAULT

// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.

package math

func isOddInt(x float64) bool {
	if Abs(x) >= (1 << 53) {
		// 1 << 53 is the largest exact integer in the float64 format.
		// Any number outside this range will be truncated before the decimal point and therefore will always be
		// an even integer.

divides the drives you provide into erasure-coding sets of *2 to 16* drives.  Therefore, the number of drives you present must be a multiple of one of these numbers.  Each object is written to a single erasure-coding set.

Minio uses the largest possible EC set size which divides into the number of drives given. For example, *18 drives* are configured as *2 sets of 9 drives*, and *24 drives* are configured as *2 sets of 12 drives*.  This is true for scenarios when running MinIO as a standalone...

var tooLargeResourceVersionCauseMsg = "Too large resource version"

// NewTooLargeResourceVersionError returns a timeout error with the given retrySeconds for a request for
// a minimum resource version that is larger than the largest currently available resource version for a requested resource.
func NewTooLargeResourceVersionError(minimumResourceVersion, currentRevision uint64, retrySeconds int) error {