테스트해보기:

* 여러 브라우저 탭에서 앱을 엽니다.
* 각 탭에서 메시지를 작성합니다.
* 한 탭을 닫아보세요.

`WebSocketDisconnect` 예외가 발생하며, 다른 모든 클라이언트가 다음과 같은 메시지를 수신합니다:

```
Client #1596980209979 left the chat
```

/// tip | 팁

위 응용 프로그램은 여러 WebSocket 연결에 메시지를 브로드캐스트하는 방법을 보여주는 간단한 예제입니다.

그러나 모든 것을 메모리의 단일 리스트로 처리하므로, 프로세스가 실행 중인 동안만 동작하며 단일 프로세스에서만 작동합니다.

    private final Map<String, byte[]> rawKeys = new ConcurrentHashMap<>();
    private final SecureRandom secureRandom = new SecureRandom();
    private KeyStore keyStore;
    private char[] keyStorePassword;
    private volatile boolean closed = false;

    /**
     * Create a secure key manager without KeyStore
     */
    public SecureKeyManager() {
        this.keyStore = null;

     * @param shareAccess the share access mode
     * @param extFileAttributes the extended file attributes
     * @param createOptions the create options
     * @param andx the next command in the chain
     */
    public SmbComNTCreateAndX(final Configuration config, final String name, final int flags, final int access, final int shareAccess,

    itself is empty.

## Version 3.9.0

_2017-09-03_

 *  **Interceptors are more capable.** The `Chain` interface now offers access
    to the call and can adjust all call timeouts. Note that this change is
    source-incompatible for code that implements the `Chain` interface.
    We don't expect this to be a problem in practice!

 *  **OkHttp has an experimental new API for tracking metrics.** The new

            return doNameQuery(name, svr);
        }

        int IP = 0x00;
        int hitDots = 0;
        final char[] data = host.toCharArray();

        for (int i = 0; i < data.length; i++) {
            char c = data[i];
            if (c < 48 || c > 57) {
                return doNameQuery(name, svr);
            }
            int b = 0x00;
            while (c != '.') {

     * @param out the writer
     * @return the number of characters copied
     */
    protected static int copyInternal(final Reader in, final Writer out) {
        try {
            final char[] buf = new char[DEFAULT_BUF_SIZE];
            int len;
            int amount = 0;
            while ((len = in.read(buf)) != -1) {
                out.write(buf, 0, len);
                amount += len;
            }

    assertEquals(Object[].class, TypeToken.of(Object[][].class).getComponentType().getType());
    assertEquals(char.class, TypeToken.of(char[].class).getComponentType().getType());
    assertEquals(char[].class, TypeToken.of(char[][].class).getComponentType().getType());
    assertEquals(byte.class, TypeToken.of(byte[].class).getComponentType().getType());

        byte[] data = new byte[] { 0x04, 0x00, 0x00, 0x00, // total
                0x01, 0x00, 0x00, 0x00, // unused
                0x02, 0x00, 0x00, 0x00, // used
                0x00, 0x00, // unused char
                0x41, 0x00, // 'A'
                0x42, 0x00 // 'B'
        };
        PacDataInputStream pdis = createInputStream(data);
        String str = pdis.readString();
        assertEquals("AB", str);

        StringBuilder sb = new StringBuilder();
        for (int i = offset; i < offset + length && buffer[i] != 0; i++) {
            if (buffer[i] != 0) {
                sb.append((char) buffer[i]);
            }
        }
        return sb.toString();
    }

   */
  public String join(Iterable<?> parts) {
    /*
     * If we can quickly determine how many elements there are likely to be, then we can use the
     * fastest possible implementation, which delegates to the array overload of String.join.
     *
     * In theory, we can quickly determine the size of any Collection. However, thanks to