ModelBuilderRequest.ModelBuilderRequestBuilder request = ModelBuilderRequest.builder();
        request.requestType(ModelBuilderRequest.RequestType.CONSUMER_POM);
        request.session(iSession);
        // in order to resolve parents, we need to fake being at the correct location
        request.source(new PomConsumerModelSource(project.getModel().getPomPath(), src));
        request.locationTracking(false);

		}
		stripPartial := strings.TrimSuffix(h, ".svc")
		if unique.Contains(stripPartial) && stripPartial != h {
			shouldDelete.Insert(h)
		}
	}
	// Filter from original list to keep original order
	ret := make([]string, 0, len(domains))
	for _, h := range domains {
		if !shouldDelete.Contains(h) {
			ret = append(ret, h)
		}
	}
	return ret
}

However, the order of those events compared to the evaluation
and indexing of <code>x</code> and the evaluation
of <code>y</code> is not specified.
</p>

<pre>
a := 1
f := func() int { a++; return a }
x := []int{a, f()}            // x may be [1, 2] or [2, 2]: evaluation order between a and f() is not specified

  /**
   * Returns the index of the first matching BMP character in a character sequence, or {@code -1} if
   * no matching character is present.
   *
   * <p>The default implementation iterates over the sequence in forward order calling {@link
   * #matches} for each character.
   *
   * @param sequence the character sequence to examine from the beginning
   * @return an index, or {@code -1} if no character matches
   */

        removeFrom.remove();
        result = true;
      }
    }
    return result;
  }

  /**
   * Determines whether two iterators contain equal elements in the same order. More specifically,
   * this method returns {@code true} if {@code iterator1} and {@code iterator2} contain the same
   * number of elements and every element of {@code iterator1} is equal to the corresponding element

            .build();
    g2.addEdge(N1, N2, E12);

    assertThat(network).isEqualTo(g2);
  }

  // Node/edge sets and node/edge connections are the same, but edge order differs.
  // (In this case the networks are considered equivalent; the edge add orderings are irrelevant.)
  @Test
  public void equivalent_edgeAddOrdersDiffer() {
    NetworkBuilder<Integer, String> builder =

            .build();
    g2.addEdge(N1, N2, E12);

    assertThat(network).isEqualTo(g2);
  }

  // Node/edge sets and node/edge connections are the same, but edge order differs.
  // (In this case the networks are considered equivalent; the edge add orderings are irrelevant.)
  @Test
  public void equivalent_edgeAddOrdersDiffer() {
    NetworkBuilder<Integer, String> builder =

in connection with its distribution of the Program in a commercial product
offering. The obligations in this section do not apply to any claims or Losses
relating to any actual or alleged intellectual property infringement. In order
to qualify, an Indemnified Contributor must: a) promptly notify the Commercial
Contributor in writing of such claim, and b) allow the Commercial Contributor
to control, and cooperate with the Commercial Contributor in, the defense

      h1 = fmix64(h1);
      h2 = fmix64(h2);

      h1 += h2;
      h2 += h1;

      return HashCode.fromBytesNoCopy(
          ByteBuffer.wrap(new byte[CHUNK_SIZE])
              .order(ByteOrder.LITTLE_ENDIAN)
              .putLong(h1)
              .putLong(h2)
              .array());
    }

    private static long fmix64(long k) {
      k ^= k >>> 33;
      k *= 0xff51afd7ed558ccdL;

                return rx - lx;
            } else {
                return lx - rx;
            }
        };

        Map<String, Lifecycle> lifecyclesMap = lookupLifecycles();

        // ensure canonical order of standard lifecycles
        return lifecyclesMap.values().stream()
                .peek(l -> Objects.requireNonNull(l.getId(), "A lifecycle must have an id."))