assertEquals(expectedHashCode.asLong.longValue(), hash.asLong());
    }
    assertThat(hash.toString()).isEqualTo(expectedHashCode.toString);
    assertSideEffectFree(hash);
    assertReadableBytes(hash);
  }

  private static void assertSideEffectFree(HashCode hash) {
    byte[] original = hash.asBytes();
    byte[] mutated = hash.asBytes();
    mutated[0]++;
    assertThat(hash.asBytes()).isEqualTo(original);
  }

      assertEquals(expectedHashCode.asLong.longValue(), hash.asLong());
    }
    assertThat(hash.toString()).isEqualTo(expectedHashCode.toString);
    assertSideEffectFree(hash);
    assertReadableBytes(hash);
  }

  private static void assertSideEffectFree(HashCode hash) {
    byte[] original = hash.asBytes();
    byte[] mutated = hash.asBytes();
    mutated[0]++;
    assertThat(hash.asBytes()).isEqualTo(original);
  }

   *       y}, if {@code equivalent(x, y)}, then {@code hash(x) == hash(y)}. It is <i>not</i>
   *       necessary that the hash be distributable across <i>inequivalence</i>. If {@code
   *       equivalence(x, y)} is false, {@code hash(x) == hash(y)} may still be true.
   *   <li>{@code hash(null)} is {@code 0}.
   * </ul>
   */
  public final int hash(@Nullable T t) {
    if (t == null) {
      return 0;
    }

        // Verify hash is not null
        byte[] hash = transport.getPreauthIntegrityHash();
        assertNotNull(hash);

        // Verify hash is a copy, not the original
        byte[] hash2 = transport.getPreauthIntegrityHash();
        assertNotSame(hash, hash2);
        assertArrayEquals(hash, hash2);
    }

    /**
     * Test that pre-auth hash is reset on error
     */
    @Test

  // }
  //
  // The imaginary `hash` and `next` values are combined into a single `int` value in the `entries`
  // array. The top bits of this value are the remaining bits of the hash value that were not used
  // in the short hash. We saw that a mask of 0x7f would keep the 7-bit value 0x6f from a full
  // hashcode of 0x89abcdef. The imaginary `hash` value would then be the remaining top 25 bits,

        assertArrayEquals(testHash, avChannelBindings.getRaw(), "Value should match the provided hash");
    }

    /**
     * Test that the constructor handles a null channel binding hash.
     */
    @Test
    void testConstructorWithNullHash() {
        AvChannelBindings avChannelBindings = new AvChannelBindings(null);

   *   <li>another java.util.Set delegate implementation. In most modern JDKs, normal java.util hash
   *       collections intelligently fall back to a binary search tree if hash table collisions are
   *       detected. Rather than going to all the trouble of reimplementing this ourselves, we
   *       simply switch over to use the JDK implementation wholesale if probable hash flooding is

    assertEquals(hashCode, hasher.hash().asLong());

    hasher = HASH_FN.newHasher();
    hasher.putLong(0x0000000001000101L);
    assertEquals(hashCode, hasher.hash().asLong());

    hasher = HASH_FN.newHasher();
    hasher
        .putShort((short) 0x0101)
        .putShort((short) 0x0100)
        .putShort((short) 0x0000)
        .putShort((short) 0x0000);
    assertEquals(hashCode, hasher.hash().asLong());
  }

  // }
  //
  // The imaginary `hash` and `next` values are combined into a single `int` value in the `entries`
  // array. The top bits of this value are the remaining bits of the hash value that were not used
  // in the short hash. We saw that a mask of 0x7f would keep the 7-bit value 0x6f from a full
  // hashcode of 0x89abcdef. The imaginary `hash` value would then be the remaining top 25 bits,

 * limitations under the License.
 */

package com.google.common.hash;

import static com.google.common.hash.Hashing.md5;
import static com.google.common.hash.Hashing.sha1;
import static com.google.common.hash.Hashing.sha256;
import static com.google.common.hash.Hashing.sha384;
import static com.google.common.hash.Hashing.sha512;
import static com.google.common.truth.Truth.assertThat;