given-names: Jeffrey
  - family-names: Devin
    given-names: Matthieu
  - family-names: Ghemawat
    given-names: Sanjay
  - family-names: Goodfellow
    given-names: Ian
  - family-names: Harp
    given-names: Andrew
  - family-names: Irving
    given-names: Geoffrey
  - family-names: Isard
    given-names: Michael
  - family-names: Jozefowicz
    given-names: Rafal
  - family-names: Jia

    avatarUrl: https://avatars.githubusercontent.com/u/9536869?u=652dd0d49717803c0cbcbf44f7740e53cf2d4892&v=4
    url: https://github.com/DMantis
  - login: hard-coders
    avatarUrl: https://avatars.githubusercontent.com/u/9651103?u=95db33927bbff1ed1c07efddeb97ac2ff33068ed&v=4
    url: https://github.com/hard-coders
  - login: supdann
    avatarUrl: https://avatars.githubusercontent.com/u/9986994?u=9671810f4ae9504c063227fee34fd47567ff6954&v=4

  static <R, C, V> RegularImmutableTable<R, C, V> forOrderedComponents(
      ImmutableList<Cell<R, C, V>> cellList,
      ImmutableSet<R> rowSpace,
      ImmutableSet<C> columnSpace) {
    // use a dense table if more than half of the cells have values
    // TODO(gak): tune this condition based on empirical evidence
    return (cellList.size() > (((long) rowSpace.size() * columnSpace.size()) / 2))

* full-stack: full-stack (do not translate to "de pila completa")
* stack: stack (do not translate to "pila")
* loop (as in async loop): loop (do not translate to "bucle" or "ciclo")
* hard dependencies: dependencias obligatorias (do not translate to "dependencias duras")
* locking: locking (do not translate to "bloqueo")
* testing (as in software testing): escribir pruebas (do not translate to "probar")

`secrets.compare_digest()` benötigt `bytes` oder einen `str`, welcher nur ASCII-Zeichen (solche der englischen Sprache) enthalten darf, das bedeutet, dass es nicht mit Zeichen wie `á`, wie in `Sebastián`, funktionieren würde.

Um dies zu lösen, konvertieren wir zunächst den `username` und das `password` in UTF-8-codierte `bytes`.

FE20..FE23    ; valid                                  # 1.1  COMBINING LIGATURE LEFT HALF..COMBINING DOUBLE TILDE RIGHT HALF
FE24..FE26    ; valid                                  # 5.1  COMBINING MACRON LEFT HALF..COMBINING CONJOINING MACRON
FE27..FE2D    ; valid                                  # 7.0  COMBINING LIGATURE LEFT HALF BELOW..COMBINING CONJOINING MACRON BELOW

   */
  /*
   * The new array contains nulls, even if the old array did not. If we wanted to be accurate, we
   * would declare a return type of `@Nullable T[]`. However, we've decided not to think too hard
   * about arrays for now, as they're a mess. (We previously discussed this in the review of
   * ObjectArrays, which is the main caller of this method.)
   */

      // return condition1 || condition2;
      if (nodeU().equals(other.nodeU())) { // check condition1
        // Here's the tricky bit. We don't have to explicitly check for condition2 in this case.
        // Why? The second half of condition2 requires that nodeV equals other.nodeU.
        // We already know that nodeU equals other.nodeU. Combined with the earlier statement,

		}
	}
	return nil
}

// bitrotSelfTest performs a self-test to ensure that bitrot
// algorithms compute correct checksums. If any algorithm
// produces an incorrect checksum it fails with a hard error.
//
// bitrotSelfTest tries to catch any issue in the bitrot implementation
// early instead of silently corrupting data.
func bitrotSelfTest() {
	checksums := map[BitrotAlgorithm]string{

{* ../../docs_src/body/tutorial001_py310.py hl[16] *}

...y declara su tipo como el modelo que creaste, `Item`.

## Resultados

Con solo esa declaración de tipo en Python, **FastAPI** hará lo siguiente:

* Leer el body del request como JSON.
* Convertir los tipos correspondientes (si es necesario).
* Validar los datos.