/**
   * Returns the number of nanoseconds of the given duration without throwing or overflowing.
   *
   * <p>Instead of throwing {@link ArithmeticException}, this method silently saturates to either
   * {@link Long#MAX_VALUE} or {@link Long#MIN_VALUE}. This behavior can be useful when decomposing
   * a duration in order to call a legacy API which requires a {@code long, TimeUnit} pair.
   */
  @SuppressWarnings({

            .size());
    // 13 elements overflow an int
    assertEquals(
        Integer.MAX_VALUE,
        Collections2.orderedPermutations(newArrayList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13))
            .size());
    // 21 elements overflow a long
    assertEquals(
        Integer.MAX_VALUE,
        Collections2.orderedPermutations(
                newArrayList(

    this.comparator = checkNotNull(comparator, "comparator");
    this.k = k;
    checkArgument(k >= 0, "k (%s) must be >= 0", k);
    checkArgument(k <= Integer.MAX_VALUE / 2, "k (%s) must be <= Integer.MAX_VALUE / 2", k);
    this.buffer = (T[]) new Object[IntMath.checkedMultiply(k, 2)];
    this.bufferSize = 0;
    this.threshold = null;
  }

  /**

          .add(i)
          .add(Long.MAX_VALUE + i)
          .add(Long.MIN_VALUE + i)
          .add(Integer.MIN_VALUE + i)
          .add(Integer.MAX_VALUE + i)
          .add(floatConversionTest + i)
          .add(doubleConversionTest + i);
      BigInteger bigI = BigInteger.valueOf(i);
      testBigIntegersBuilder
          .add(bigI)
          .add(BigInteger.valueOf(Long.MAX_VALUE).add(bigI))

 */

package com.google.common.collect;

import static com.google.common.collect.Lists.newArrayList;
import static com.google.common.truth.Truth.assertThat;
import static java.lang.Long.MAX_VALUE;
import static java.lang.Thread.currentThread;
import static java.util.concurrent.Executors.newCachedThreadPool;
import static java.util.concurrent.TimeUnit.MILLISECONDS;
import static java.util.concurrent.TimeUnit.NANOSECONDS;

          .add(i)
          .add(Long.MAX_VALUE + i)
          .add(Long.MIN_VALUE + i)
          .add(Integer.MIN_VALUE + i)
          .add(Integer.MAX_VALUE + i)
          .add(floatConversionTest + i)
          .add(doubleConversionTest + i);
      BigInteger bigI = BigInteger.valueOf(i);
      testBigIntegersBuilder
          .add(bigI)
          .add(BigInteger.valueOf(Long.MAX_VALUE).add(bigI))

    Double.NEGATIVE_INFINITY,
    -Double.MAX_VALUE,
    (double) Long.MIN_VALUE,
    (double) Integer.MIN_VALUE,
    -Math.PI,
    -1.0,
    -Double.MIN_VALUE,
    -0.0,
    +0.0,
    Double.MIN_VALUE,
    1.0,
    Math.PI,
    (double) Integer.MAX_VALUE,
    (double) Long.MAX_VALUE,
    Double.MAX_VALUE,
    Double.POSITIVE_INFINITY,
    Double.NaN,
    Float.MAX_VALUE,
  };

   * Duplicated from LongMath.
   * binomial(biggestBinomials[k], k) fits in a long, but not
   * binomial(biggestBinomials[k] + 1, k).
   */
  static final int[] biggestBinomials = {
    Integer.MAX_VALUE,
    Integer.MAX_VALUE,
    Integer.MAX_VALUE,
    3810779,
    121977,
    16175,
    4337,
    1733,
    887,
    534,
    361,
    265,
    206,
    169,
    143,
    125,
    111,
    101,

   */
  public void testNulls() {}

  public void testOverflows() {
    LongAdder longAdder = new LongAdder();
    longAdder.add(Long.MAX_VALUE);
    assertThat(longAdder.sum()).isEqualTo(Long.MAX_VALUE);
    longAdder.add(1);
    // silently overflows; is this a bug?
    // See https://github.com/google/guava/issues/3503
    assertThat(longAdder.sum()).isEqualTo(-9223372036854775808L);
  }

    int scale = Integer.MAX_VALUE;
    int otherIndex = (Integer.MAX_VALUE - 1) / 3; // this divides exactly
    // For the otherIndex calculation, we have q=Integer.MAX_VALUE, k=(Integer.MAX_VALUE-1)/3, and
    // N=16. Therefore k*(N-1)/q = 5-5/Integer.MAX_VALUE, which has floor 4 and fractional part
    // (1-5/Integer.MAX_VALUE).
    double otherValue = 16.0 * 5.0 / Integer.MAX_VALUE + 25.0 * (1.0 - 5.0 / Integer.MAX_VALUE);