bits; excess != 0 { b[0] >>= excess } // Don't let the value be too small: set the most significant two bits. // Setting the top two bits, rather than just the top bit, means that // when two of these values are multiplied together, the result isn't // ever one bit short. if excess := len(b)*8 - bits; excess < 7 { b[0] |= 0b1100_0000 >> excess } else { b[0] |= 0b0000_0001 b[1] |= 0b1000_0000 } // Make the value odd since an even number certainly isn't prime. b[len(b)-1] |= 1 // We don't need to check...