// of A, B, C, and D, so when scanning B and D, E will be added again 'filtered'.
        //
        // Without de-duplication, the final list would contain E three times, once for E being in the projects and
        // whitelisted, and twice more for E being a downstream dependency of B and D.
        return filtered.stream().distinct().toList();
    }

    @Override

// A zero value for t means I/O operations will not time out.
func (c *DeadlineConn) SetDeadline(t time.Time) error {
	c.mu.Lock()
	defer c.mu.Unlock()

	c.readSetAt = time.Time{}
	c.writeSetAt = time.Time{}
	c.abortReads.Store(!t.IsZero() && time.Until(t) < 0)
	c.abortWrites.Store(!t.IsZero() && time.Until(t) < 0)
	c.infReads.Store(t.IsZero())
	c.infWrites.Store(t.IsZero())

  private var waitingCoordinatorTask: SerialTask? = null
  private var waitingCoordinatorInterrupted = false
  private var waitingCoordinatorNotified = false

  /** How many times a new task has been started. Guarded by `this`. */
  private var contextSwitchCount = 0

  /** Guarded by `this`. */
  private var activeThreads = 0

   * escaping for code points if required.
   *
   * <p>Note that arrays returned by this method must not be modified once they have been returned.
   * However it is acceptable to return the same array multiple times (even for different input
   * characters).
   *
   * @param cp the Unicode code point to escape
   * @return the replacement characters, or {@code null} if no escaping was required
   */

   */
  @Override
  Set<N> successors(N node);

  /**
   * Returns the count of {@code node}'s incident edges, counting self-loops twice (equivalently,
   * the number of times an edge touches {@code node}).
   *
   * <p>For directed graphs, this is equal to {@code inDegree(node) + outDegree(node)}.
   *
   * <p>For undirected graphs, this is equal to {@code incidentEdges(node).size()} + (number of

   * original transformation and its inverse to a value gives you the original value give-or-take
   * numerical errors. Calling this method multiple times on the same instance will always return
   * the same instance. Calling this method on the result of calling this method on an instance will
   * always return that original instance.
   */

   * note that the execution order of all listeners is ultimately chosen by the implementations of
   * the supplied executors.
   *
   * <p>This method is idempotent. Calling it several times in parallel is semantically equivalent
   * to calling it exactly once.
   *
   * @since 10.0 (present in 1.0 as {@code run})
   */
  public void execute() {

   *         .putEdge(GERMANY, BELGIUM)
   *         .addNode(ICELAND)
   *         .build();
   * }
   *
   * <p>Builder instances can be reused; it is safe to call {@link #build} multiple times to build
   * multiple graphs in series. Each new graph contains all the elements of the ones created before
   * it.
   *
   * @since 28.0
   */
  public static class Builder<N> {

          // Consume and discard the response body.
          body.source().readByteString();
        }
      }
    });

    Request newYorkTimesRequest = new Request.Builder()
        .url("https://www.nytimes.com/")
        .build();
    client.newCall(newYorkTimesRequest).enqueue(new Callback() {
      @Override public void onFailure(Call call, IOException e) {
      }

   * scheduled. If the task is already in the queue, the earliest execution time is used.
   *
   * The target execution time is implemented on a best-effort basis. If another task in this queue
   * is running when that time is reached, that task is allowed to complete before this task is
   * started. Similarly the task will be delayed if the host lacks compute resources.
   *