}

  @Override
  public CollectionSize getCollectionSize() {
    return collectionSize;
  }

  @Override
  public Iterable<E> order(List<E> insertionOrder) {
    return generator.order(insertionOrder);
  }

   * may be false for some instances where the statistics are mathematically equal, including
   * instances constructed from the same values in a different order... or (in the general case)
   * even in the same order. (It is guaranteed to return true for instances constructed from the
   * same values in the same order if {@code strictfp} is in effect, or if the system architecture
   * guarantees {@code strictfp}-like semantics.)
   */
  @Override

    }

    @Override
    public E[] createArray(int length) {
      return gen.createArray(length);
    }

    @Override
    public Iterable<E> order(List<E> insertionOrder) {
      return gen.order(insertionOrder);
    }
  }

  private static Set<Feature<?>> computeReserializedCollectionFeatures(Set<Feature<?>> features) {
    Set<Feature<?>> derivedFeatures = new HashSet<>(features);

    assertEquals(expected, murmur3_128(seed).newHasher().putBytes(input).hash());
  }

  /** Returns a {@link HashCode} for a sequence of longs, in big-endian order. */
  private static HashCode toHashCode(long... longs) {
    ByteBuffer bb = ByteBuffer.wrap(new byte[longs.length * 8]).order(ByteOrder.LITTLE_ENDIAN);
    for (long x : longs) {
      bb.putLong(x);
    }
    return HashCode.fromBytes(bb.array());
  }

    addNodes(graph);

    assertThat(graph.nodeOrder())
        .isEqualTo(ElementOrder.sorted(Ordering.<Integer>natural().reverse()));
    assertThat(graph.nodes()).containsExactly(4, 3, 1).inOrder();
  }

  // Edge order tests

  @Test
  public void edgeOrder_none() {
    MutableNetwork<Integer, String> network =
        NetworkBuilder.directed().edgeOrder(unordered()).build();

            EndpointPair.unordered(1, 1),
            EndpointPair.unordered(1, 3))
        .inOrder();
  }

  /**
   * Populates the graph with nodes and edges in a star shape with node `1` in the middle.
   *
   * <p>Note that the edges are added in a shuffled order to properly test the effect of the
   * insertion order.
   */
  private void populateTShapedGraph() {
    putEdge(2, 1);
    putEdge(1, 4);

Dann gehen Sie zur Theke 🔀, zur ursprünglichen Aufgabe, die nun erledigt ist ⏯, nehmen die Burger auf, sagen Danke, und bringen sie zum Tisch. Damit ist dieser Schritt / diese Aufgabe der Interaktion mit der Theke abgeschlossen ⏹. Das wiederum schafft eine neue Aufgabe, „Burger essen“ 🔀 ⏯, aber die vorherige Aufgabe „Burger holen“ ist erledigt ⏹.

### Parallele Hamburger

    @Override
    public Entry<String, Integer>[] createArray(int length) {
      return (Entry<String, Integer>[]) new Entry<?, ?>[length];
    }

    @Override
    public Iterable<Entry<String, Integer>> order(List<Entry<String, Integer>> insertionOrder) {
      return new Ordering<Entry<String, Integer>>() {
        @Override
        public int compare(Entry<String, Integer> left, Entry<String, Integer> right) {

    assertThat(multimap.get("foo")).containsExactly(1, 3, 7).inOrder();
    assertThat(multimap.get("google")).containsExactly(2, 6).inOrder();
    assertThat(multimap.get("tree")).containsExactly(0, 4).inOrder();
  }

  public void testOrderedKeySet() {
    TreeMultimap<String, Integer> multimap = createPopulate();
    assertThat(multimap.keySet()).containsExactly("foo", "google", "tree").inOrder();
  }

                    populateForRowKeySet(table, elements);
                    return table.rowKeySet();
                  }

                  @Override
                  public List<String> order(List<String> insertionOrder) {
                    sort(insertionOrder);
                    return insertionOrder;
                  }
                })
            .named("TreeBasedTable.rowKeySet")