{
			bucketName:         bucketName,
			objectName:         objectName,
			data:               bytesData,
			dataLen:            len(bytesData),
			chunkSize:          64 * humanize.KiByte,
			expectedContent:    []byte{},
			expectedRespStatus: http.StatusOK,
			accessKey:          credentials.AccessKey,
			secretKey:          credentials.SecretKey,
			shouldPass:         true,

github.com/shoenig/go-m1cpu v0.1.6 h1:nxdKQNcEB6vzgA2E2bvzKIYRuNj7XNJ4S/aRSwKzFtM=
github.com/shoenig/go-m1cpu v0.1.6/go.mod h1:1JJMcUBvfNwpq05QDQVAnx3gUHr9IYF7GNg9SUEw2VQ=
github.com/shoenig/test v0.6.4 h1:kVTaSd7WLz5WZ2IaoM0RSzRsUD+m8wRR+5qvntpn4LU=
github.com/shoenig/test v0.6.4/go.mod h1:byHiCGXqrVaflBLAMq/srcZIHynQPQgeyvkvXnjqq0k=
github.com/sirupsen/logrus v1.4.2/go.mod h1:tLMulIdttU9McNUspp0xgXVQah82FyeX6MwdIuYE2rE=

     *
     * The key idea is that based on the number of leading zeros (equivalently, floor(log2(x))), we
     * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
     * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
     */
    int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
    /*

    private SMBSigningDigest digest;

    private final Semaphore credits = new Semaphore(1, true);

    private final int desiredCredits = 512;

    private byte[] preauthIntegrityHash = new byte[64];


    SmbTransportImpl ( CIFSContext tc, Address address, int port, InetAddress localAddr, int localPort, boolean forceSigning ) {
        this.transportContext = tc;

# WINDOWS X86-64 CPU PYCPP
test:windows_x86_cpu_pycpp_test_filters --test_tag_filters=-no_windows,-windows_excluded,-no_oss,-oss_excluded,-gpu,-tpu,-benchmark-test

	if !ok {
		s.writeErrorResponse(w, errAuthentication)
		return
	}

	size, err := strconv.Atoi(sizeStr)
	if err != nil {
		size = 64 * humanize.MiByte
	}

	concurrent, err := strconv.Atoi(concurrentStr)
	if err != nil {
		concurrent = 32
	}

	duration, err := time.ParseDuration(durationStr)
	if err != nil {

                }
              }
            ]
          }
        ]
      },
      "gridPos": {
        "h": 6,
        "w": 6,
        "x": 12,
        "y": 12
      },
      "id": 64,
      "options": {
        "legend": {
          "calcs": [],
          "displayMode": "list",
          "placement": "bottom",
          "showLegend": true
        },
        "tooltip": {

     *
     * The key idea is that based on the number of leading zeros (equivalently, floor(log2(x))), we
     * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
     * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
     */
    int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
    /*

- login: ghandic
  count: 71
  avatarUrl: https://avatars.githubusercontent.com/u/23500353?u=e2e1d736f924d9be81e8bfc565b6d8836ba99773&v=4
  url: https://github.com/ghandic
- login: JavierSanchezCastro
  count: 64
  avatarUrl: https://avatars.githubusercontent.com/u/72013291?u=ae5679e6bd971d9d98cd5e76e8683f83642ba950&v=4
  url: https://github.com/JavierSanchezCastro
- login: falkben
  count: 59

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