.addEqualityGroup(Ordering.natural())
        .testEquals();
  }

  public void testIsInOrder() {
    assertFalse(isInOrder(asList(5, 3, 0, 9), Ordering.natural()));
    assertFalse(isInOrder(asList(0, 5, 3, 9), Ordering.natural()));
    assertTrue(isInOrder(asList(0, 3, 5, 9), Ordering.natural()));
    assertTrue(isInOrder(asList(0, 0, 3, 3), Ordering.natural()));

 *
 * @author Chris Povirk
 * @author Jared Levy
 */
@GwtCompatible
@ElementTypesAreNonnullByDefault
public abstract class TestIntegerSortedSetGenerator extends TestIntegerSetGenerator {
  @Override
  protected abstract SortedSet<Integer> create(Integer[] elements);

  /** Sorts the elements by their natural ordering. */
  @Override

    assertEquals(tree, copyFromTree);
    assertSame(Ordering.natural(), copyFromTree.keyComparator());
    assertSame(Ordering.natural(), copyFromTree.valueComparator());
    assertSame(Ordering.natural(), copyFromTree.get(1.0).comparator());
  }

  /** Test that creating one TreeMultimap from a non-TreeMultimap results in natural ordering. */
  public void testCreateFromHashMultimap() {

  }

  @Test
  public void nodeOrder_natural() {
    MutableGraph<Integer> graph =
        GraphBuilder.directed().nodeOrder(ElementOrder.<Integer>natural()).build();

    addNodes(graph);

    assertThat(graph.nodeOrder()).isEqualTo(ElementOrder.sorted(Ordering.<Integer>natural()));
    assertThat(graph.nodes()).containsExactly(1, 3, 4).inOrder();
  }

  @Test
  public void nodeOrder_sorted() {

  }

  public static <E extends Comparable<? super E>> ImmutableSortedSet<E> of(E e1) {
    return ofInternal(Ordering.natural(), e1);
  }

  @SuppressWarnings("unchecked")
  public static <E extends Comparable<? super E>> ImmutableSortedSet<E> of(E e1, E e2) {
    return ofInternal(Ordering.natural(), e1, e2);
  }

  @SuppressWarnings("unchecked")

    ImmutableTable.Builder<Character, Integer, String> builder = ImmutableTable.builder();
    Table<Character, Integer, String> copy =
        builder
            .orderRowsBy(Ordering.natural())
            .orderColumnsBy(Ordering.natural())
            .putAll(table)
            .build();
    assertThat(copy.rowKeySet()).containsExactly('a', 'b').inOrder();
    assertThat(copy.columnKeySet()).containsExactly(1, 2).inOrder();

 *       directly
 *   <li>Pass a <i>pre-existing</i> {@link Comparator} instance to {@link #from(Comparator)}
 *   <li>Use the natural ordering, {@link Ordering#natural}
 * </ul>
 *
 * <h4>Chaining</h4>
 *
 * <p>Then you can use the <i>chaining</i> methods to get an altered version of that {@code
 * Ordering}, including:
 *
 * <ul>
 *   <li>{@link #reverse}

    // Before JDK6 (including under GWT), the TreeMap keySet is a plain Set.
    if (Maps.newTreeMap().keySet() instanceof SortedSet) {
      assertTrue(SortedIterables.hasSameComparator(Ordering.natural(), Maps.newTreeMap().keySet()));
    }
    assertTrue(
        SortedIterables.hasSameComparator(

    // Before JDK6 (including under GWT), the TreeMap keySet is a plain Set.
    if (Maps.newTreeMap().keySet() instanceof SortedSet) {
      assertTrue(SortedIterables.hasSameComparator(Ordering.natural(), Maps.newTreeMap().keySet()));
    }
    assertTrue(
        SortedIterables.hasSameComparator(

        .addEqualityGroup(Ordering.natural())
        .testEquals();
    reserializeAndAssert(comparator);
    assertEquals("Ordering.natural().reverse().onResultOf(StringLength)", comparator.toString());
  }

  public void testLexicographical() {
    Ordering<String> ordering = Ordering.natural();
    Ordering<Iterable<String>> lexy = ordering.lexicographical();