int encoded3 = request.encode(buffer3, 0);

        // All should produce same result
        assertEquals(encoded1, encoded2);
        assertEquals(encoded2, encoded3);

        // Compare actual bytes (up to encoded length)
        for (int i = 0; i < encoded1; i++) {
            assertEquals(buffer1[i], buffer2[i], "Mismatch at position " + i);

    for (double x : VALUES) {
      for (double y : VALUES) {
        // note: spec requires only that the sign is the same
        assertWithMessage("%s, %s", x, y)
            .that(Doubles.compare(x, y))
            .isEqualTo(Double.compare(x, y));
      }
    }
  }

  public void testContains() {
    assertThat(Doubles.contains(EMPTY, 1.0)).isFalse();
    assertThat(Doubles.contains(ARRAY1, 2.0)).isFalse();

		if err != nil {
			writeCustomErrorResponseJSON(ctx, w, errorCodes.ToAPIErr(ErrInternalError), err.Error(), r.URL)
			return
		}
		writeSuccessResponseJSON(w, resp)
		return
	}

	// 3. Compare generated key with decrypted key
	if subtle.ConstantTimeCompare(key.Plaintext, decryptedKey) != 1 {
		response.DecryptionErr = "The generated and the decrypted data key do not match"
		resp, err := json.Marshal(response)

                    sort(
                        insertionOrder,
                        new Comparator<Entry<String, Integer>>() {
                          @Override
                          public int compare(Entry<String, Integer> o1, Entry<String, Integer> o2) {
                            return o1.getKey().compareTo(o2.getKey());
                          }
                        });
                    return insertionOrder;

     * hashes (meaning negotiated via NTLM HTTP Authentication) and the other does not they will not be equal. This is
     * technically not correct however the server 8 byte challenge would be required to compute and compare the password
     * hashes but that it not available with this method.
     */
    @Override
    public boolean equals(final Object obj) {
        if (super.equals(obj)) {

pkg net/http, type ClientConn struct #75772
pkg net/http, type HTTP2Config struct, StrictMaxConcurrentRequests bool #67813
pkg net/http/httputil, type ReverseProxy struct, Director //deprecated #73161
pkg net/netip, method (Prefix) Compare(Prefix) int #61642
pkg os, method (*Process) WithHandle(func(uintptr)) error #70352
pkg os, var ErrNoHandle error #70352
pkg reflect, method (Value) Fields() iter.Seq2[StructField, Value] #66631

### Работа с *перечислениями* в Python { #working-with-python-enumerations }

Значение *параметра пути* будет *элементом перечисления*.

#### Сравнение *элементов перечисления* { #compare-enumeration-members }

Вы можете сравнить это значение с *элементом перечисления* класса `ModelName`:

{* ../../docs_src/path_params/tutorial005_py39.py hl[17] *}

  }

  /**
   * Returns an immutable list containing the given elements, sorted according to their natural
   * order. The sorting algorithm used is stable, so elements that compare as equal will stay in the
   * order in which they appear in the input.
   *
   * <p>If your data has no duplicates, or you wish to deduplicate elements, use {@code

  public void testCompare() {
    for (int x : VALUES) {
      for (int y : VALUES) {
        // note: spec requires only that the sign is the same
        assertWithMessage("%s, %s", x, y).that(Ints.compare(x, y)).isEqualTo(Integer.compare(x, y));
      }
    }
  }

  public void testContains() {
    assertThat(Ints.contains(EMPTY, (int) 1)).isFalse();
    assertThat(Ints.contains(ARRAY1, (int) 2)).isFalse();

pkg bytes, func ContainsFunc([]uint8, func(int32) bool) bool #54386
pkg bytes, method (*Buffer) AvailableBuffer() []uint8 #53685
pkg bytes, method (*Buffer) Available() int #53685
pkg cmp, func Compare[$0 Ordered]($0, $0) int #59488
pkg cmp, func Less[$0 Ordered]($0, $0) bool #59488
pkg cmp, type Ordered interface {} #59488
pkg context, func AfterFunc(Context, func()) func() bool #57928