if result.Pets[i-1].Name > result.Pets[i].Name {
				t.Fatalf("Preload user %v pets not ordered correctly, last %v, cur %v", result.Name, result.Pets[i-1], result.Pets[i])
			}
		}
		for i := 1; i < len(result.Pets); i++ {
			if result.Pets[i-1].Name > result.Pets[i].Name {
				t.Fatalf("Preload user %v friends not ordered correctly, last %v, cur %v", result.Name, result.Pets[i-1], result.Pets[i])
			}
		}
	}
}

 * all the dependencies.</p>
 *
 * <p>The <dfn>Dependency graph flattening</dfn> process in Maven reduces a complex,
 * multi-level dependency graph to a map of ordered lists that can be turned into classpaths.
 * During this process only the most relevant version of each artifact
 * (based on group ID and artifact ID) is retained, resolving conflicts and eliminating duplicates to ensure

  }

  protected Collection<E> getSampleElements() {
    return getSampleElements(getNumElements());
  }

  /**
   * Returns the {@linkplain #getSampleElements() sample elements} as ordered by {@link
   * TestContainerGenerator#order(List)}. Tests should use this method only if they declare
   * requirement {@link com.google.common.collect.testing.features.CollectionFeature#KNOWN_ORDER}.
   */

    assertThat(Chars.join(",", '1', '2')).isEqualTo("1,2");
    assertThat(Chars.join("", '1', '2', '3')).isEqualTo("123");
  }

  public void testLexicographicalComparator() {
    List<char[]> ordered =
        Arrays.asList(
            new char[] {},
            new char[] {LEAST},
            new char[] {LEAST, LEAST},
            new char[] {LEAST, (char) 1},
            new char[] {(char) 1},

     */
    @Size(max = 1000)
    public String defaultLabelValue;

    /**
     * Default sort order for search results.
     * Defines how search results are ordered when no specific sort is requested.
     */
    @Size(max = 1000)
    public String defaultSortValue;

    /**
     * Virtual host configuration for multi-tenant setups.

    assertThat(Booleans.join("", false, true, false)).isEqualTo("falsetruefalse");
  }

  public void testLexicographicalComparator() {
    List<boolean[]> ordered =
        Arrays.asList(
            new boolean[] {},
            new boolean[] {false},
            new boolean[] {false, false},
            new boolean[] {false, true},
            new boolean[] {true},

x solid #dee2e6}.table thead th{vertical-align:bottom;border-bottom:2px solid #dee2e6}.table tbody+tbody{border-top:2px solid #dee2e6}.table-sm td,.table-sm th{padding:.3rem}.table-bordered{border:1px solid #dee2e6}.table-bordered td,.table-bordered th{border:1px solid #dee2e6}.table-bordered thead td,.table-bordered thead th{border-bottom-width:2px}.table-borderless tbody+tbody,.table-borderless td,.table-borderless th,.table-borderless thead th{border:0}.table-striped tbody tr:nth-of-type(odd)...

    assertThat(Doubles.join(",", 1.3, 2.4)).isEqualTo("1.3,2.4");
    assertThat(Doubles.join("", 1.4, 2.5, 3.6)).isEqualTo("1.42.53.6");
  }

  public void testLexicographicalComparator() {
    List<double[]> ordered =
        Arrays.asList(
            new double[] {},
            new double[] {LEAST},
            new double[] {LEAST, LEAST},
            new double[] {LEAST, 1.0},
            new double[] {1.0},

     * @return {@code true} if passed problem is preserved by this call.
     */
    boolean reportProblem(P problem);

    /**
     * Returns all reported and preserved problems ordered by severity in decreasing order. Note: counters and
     * element count in this stream does not have to be equal.
     */
    @Nonnull
    default Stream<P> problems() {
        Stream<P> result = Stream.empty();

    assertThat(Doubles.join(",", 1.3, 2.4)).isEqualTo("1.3,2.4");
    assertThat(Doubles.join("", 1.4, 2.5, 3.6)).isEqualTo("1.42.53.6");
  }

  public void testLexicographicalComparator() {
    List<double[]> ordered =
        Arrays.asList(
            new double[] {},
            new double[] {LEAST},
            new double[] {LEAST, LEAST},
            new double[] {LEAST, 1.0},
            new double[] {1.0},