Agora, vamos ver como você pode usar isso para retornar uma resposta personalizada.

Vamos dizer quer retornar uma resposta <a href="https://pt.wikipedia.org/wiki/XML" class="external-link" target="_blank">XML</a>.

   * MoreExecutors#listeningDecorator( java.util.concurrent.ExecutorService)}, {@link
   * ListenableFutureTask}, {@link AbstractFuture}, and other utilities over creating plain {@code
   * Future} instances to be upgraded to {@code ListenableFuture} after the fact.
   */
  public static <V extends @Nullable Object> ListenableFuture<V> listenInPoolThread(
      Future<V> future) {

<details>
<summary>👀 Vollständige Dateivorschau</summary>

```Python
{!> ../../docs_src/separate_openapi_schemas/tutorial001.py!}
```

</details>

////

### Modell für Eingabe

Wenn Sie dieses Modell wie hier als Eingabe verwenden:

//// tab | Python 3.10+

```Python hl_lines="14"
{!> ../../docs_src/separate_openapi_schemas/tutorial001_py310.py[ln:1-15]!}

# Code unterhalb weggelassen 👇
```

<details>

a client certificate.

The following curl example shows how to authenticate to a MinIO server with client certificate and obtain STS access credentials.

```curl

public abstract class ForwardingImmutableSet<E> extends ImmutableSet<E> {
  private final transient Set<E> delegate;

  ForwardingImmutableSet(Set<E> delegate) {
    // TODO(cpovirk): are we over-wrapping?
    this.delegate = Collections.unmodifiableSet(delegate);
  }

  @Override
  public UnmodifiableIterator<E> iterator() {
    return Iterators.unmodifiableIterator(delegate.iterator());
  }

Porém, ao verificar benchmarks e comparações você deve prestar atenção ao seguinte:

## Benchmarks e velocidade

Quando você verifica os benchmarks, é comum ver diversas ferramentas de diferentes tipos comparados como se fossem equivalentes.

Especificamente, para ver o Uvicorn, Starlette e FastAPI comparados entre si (entre diversas outras ferramentas).

			continue
		}
		// if uv has tiered content we add a
		// free-version to track it for asynchronous
		// deletion via scanner.
		ver, err := x.getIdx(i)
		if err != nil {
			return err
		}

		if freeVersion, toFree := ver.ObjectV2.InitFreeVersion(fi); toFree {
			return x.addVersion(freeVersion)
		}
		return nil
	}
	return nil

         * distinct elements, and add the last element over again many times over. We don't want a
         * situation where we re-sort the entire buffer every time the last element is re-added.
         *
         * <p>The solution is to ensure there are O(n) spaces left over in the buffer after
         * sortAndDedup -- that is, at least c*n for some constant c > 0. Ensuring the buffer size

	m, err := readAndMap(files, 1, 0)
	if err != nil {
		return err
	}
	if m.blocks > 0 {
		// TODO: Support multiple blocks. For now use -xver.
		return fmt.Errorf("multiple blocks found, only one block supported. Try with -xver")
	}
	lastValid := 0
	missing := 0
	for i := range m.filled {
		if m.filled[i] == 1 {
			lastValid = i
		} else {
			missing++
		}
	}

   * Ordering.natural()} if the elements are ordered by their natural ordering.
   */
  Comparator<? super T> comparator();

  /**
   * Returns an iterator over elements of type {@code T}. The elements are returned in nondecreasing
   * order according to the associated {@link #comparator}.
   */
  @Override
  Iterator<T> iterator();