int columnNumber,
            String modelId,
            Exception exception) {
        this.message = message;
        this.severity = (severity != null) ? severity : Severity.ERROR;
        this.source = (source != null) ? source : "";
        this.lineNumber = lineNumber;
        this.columnNumber = columnNumber;
        this.modelId = (modelId != null) ? modelId : "";
        this.exception = exception;

specific language governing permissions and limitations
under the License.
-->

<model xmlns="http://modello.codehaus.org/MODELLO/1.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://modello.codehaus.org/MODELLO/1.0.0 http://modello.codehaus.org/xsd/modello-1.0.0.xsd"
  xml.namespace="http://maven.apache.org/PARAMDOC/${version}"

## Other models { #other-models }

You can now get the current user directly in the *path operation functions* and deal with the security mechanisms at the **Dependency Injection** level, using `Depends`.

And you can use any model or data for the security requirements (in this case, a Pydantic model `User`).

But you are not restricted to using some specific data model, class or type.

* serialização de dados
* documentação de dados, etc.

Isso funciona da mesma forma que com os modelos Pydantic. E na verdade é alcançado da mesma maneira por baixo dos panos, usando Pydantic.

/// info | Informação

Lembre-se de que dataclasses não podem fazer tudo o que os modelos Pydantic podem fazer.

Então, você ainda pode precisar usar modelos Pydantic.

* documentación de datos, etc.

Esto funciona de la misma manera que con los modelos de Pydantic. Y en realidad se logra de la misma manera internamente, utilizando Pydantic.

/// info | Información

Ten en cuenta que los dataclasses no pueden hacer todo lo que los modelos de Pydantic pueden hacer.

Así que, podrías necesitar seguir usando modelos de Pydantic.

Es wird von Pydantic **nicht unterstützt**, dass ein Pydantic‑v2‑Modell Felder hat, die als Pydantic‑v1‑Modelle definiert sind, und umgekehrt.

```mermaid
graph TB
    subgraph "❌ Nicht unterstützt"
        direction TB
        subgraph V2["Pydantic-v2-Modell"]
            V1Field["Pydantic-v1-Modell"]
        end
        subgraph V1["Pydantic-v1-Modell"]
            V2Field["Pydantic-v2-Modell"]
        end
    end

따라서 **FastAPI**는 출력 모델에서 선언하지 않은 모든 데이터를 (Pydantic을 사용하여) 필터링합니다.

## 문서에서 보기

자동 생성 문서를 보면 입력 모델과 출력 모델이 각자의 JSON 스키마를 가지고 있음을 확인할 수 있습니다:

<img src="/img/tutorial/response-model/image01.png">

그리고 두 모델 모두 대화형 API 문서에 사용됩니다:

<img src="/img/tutorial/response-model/image02.png">

## 응답 모델 인코딩 매개변수

응답 모델은 아래와 같이 기본값을 가질 수 있습니다:

{* ../../docs_src/response_model/tutorial004.py hl[11,13:14] *}

specific language governing permissions and limitations
under the License.
-->

<model xmlns="http://codehaus-plexus.github.io/MODELLO/2.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://codehaus-plexus.github.io/MODELLO/2.0.0 https://codehaus-plexus.github.io/modello/xsd/modello-2.0.0.xsd">
  <id>extension</id>
  <name>ExtensionDescriptor</name>
  <description><![CDATA[

## Use Case { #use-case }

Let's start with an example **use case** and then see how to solve it with this.

Let's imagine that you have some **machine learning models** that you want to use to handle requests. 🤖

The same models are shared among requests, so, it's not one model per request, or one per user or something similar.

/**
 * Strategy for applying Maven inference optimizations.
 * For 4.0.0 models: applies limited inference (parent-related only).
 * For 4.1.0+ models: applies full inference optimizations.
 * Removes redundant information that can be inferred by Maven during model building.
 */
@Named
@Singleton
@Priority(30)
public class InferenceStrategy extends AbstractUpgradeStrategy {