你可以同时拥有并行性和异步性，你可以获得比大多数经过测试的 NodeJS 框架更高的性能，并且与 Go 不相上下， Go 是一种更接近于 C 的编译语言（[全部归功于 Starlette](https://www.techempower.com/benchmarks/#section=data-r17&hw=ph&test=query&l=zijmkf-1)）。

### 并发比并行好吗？ { #is-concurrency-better-than-parallelism }

不！这不是故事的本意。

并发不同于并行。而是在需要大量等待的特定场景下效果更好。因此，在 Web 应用程序开发中，它通常比并行要好得多，但这并不意味着全部。

因此，为了平衡这一点，想象一下下面的短篇故事：

> 你必须打扫一个又大又脏的房子。

*是的，这就是完整的故事。*

---

&"fixed"===n.default(F).css("position"),r=n.default(this._config.target+", "+this._config.target+" "+Q);if(0===o&&0===i)t.css({bottom:a.footer,top:a.header}),r.css("height",a.window-(a.header+a.footer));else if(i<=a.footer)if(!1===s){var d=a.header-o;t.css("bottom",a.footer-i).css("top",d>=0?d:0),r.css("height",a.window-(a.footer-i))}else t.css("bottom",a.footer);else o<=a.header?!1===l?(t.css("top",a.header-o),r.css("height",a.window-(a.header-o))):t.css("top",a.header):!1===l?(t.css("top",0),r...

   * structure (to make it possible to throw ConcurrentModificationException in the iterator). Note
   * that we choose not to make this volatile, so we do less of a "best effort" to track such
   * errors, for better performance.
   *
   * <p>For a new instance, where the arrays above have not yet been allocated, the value of {@code
   * metadata} is the size that the arrays should be allocated with. Once the arrays have been

	// Start the disk monitoring and connect routine.
	if !globalIsTesting {
		go s.monitorAndConnectEndpoints(ctx, defaultMonitorConnectEndpointInterval)
	}

	return s, nil
}

// cleanup ".trash/" folder every 5m minutes with sufficient sleep cycles, between each
// deletes a dynamic sleeper is used with a factor of 10 ratio with max delay between
// deletes to be 2 seconds.

 *   <li><a target="_parent" href="http://www.cymru.com/Bogons/v6bogon.html">http://www.cymru.com/
 *       Bogons/v6bogon.html</a>
 *   <li><a target="_parent" href="http://www.space.net/~gert/RIPE/ipv6-filters.html">http://www.
 *       space.net/~gert/RIPE/ipv6-filters.html</a>
 * </ul>
 *
 * @author Erik Kline
 * @since 5.0
 */
@J2ktIncompatible
@GwtIncompatible
public final class InetAddresses {

get its source.  For example, if your program is a web application, its
interface could display a "Source" link that leads users to an archive
of the code.  There are many ways you could offer source, and different
solutions will be better for different programs; see section 13 for the
specific requirements.

  You should also get your employer (if you work as a programmer) or school,
if any, to sign a "copyright disclaimer" for the program, if necessary.

        // condition efficiently without _introducing_ deadlock is probably
        // tricky. For now, just accept the race condition---missing a warning
        // now and then is still better than having no deadlock detection.
        allowedPriorLocks.put(acquiredLock, new ExampleStackTrace(acquiredLock, this));
      } else {
        // Unsafe acquisition order detected. Create and cache a

				"application/vnd.shana.informed.package",
				"application/vnd.simtech-mindmapper",
				"application/vnd.smaf",
				"application/vnd.smart.teacher",
				"application/vnd.software602.filler.form+xml",
				"application/vnd.software602.filler.form-xml-zip",
				"application/vnd.solent.sdkm+xml",
				"application/vnd.spotfire.dxp",
				"application/vnd.spotfire.sfs",
				"application/vnd.sss-cod",
				"application/vnd.sss-dtf",

	default:
		p.errorf("register list not supported on this architecture")
	}
}

func (p *Parser) registerListX86(a *obj.Addr) {
	// Accept only [RegA-RegB] syntax.
	// Don't use p.get() to provide better error messages.

	loName := p.next().String()
	lo, ok := p.arch.Register[loName]
	if !ok {
		if loName == "EOF" {
			p.errorf("register list: expected ']', found EOF")
		} else {

                        top: containerTop,
                        right: containerRight,
                        left: 'auto'
                    });
                }
            } else if (this.opens == 'center') {
                var containerLeft = this.element.offset().left - parentOffset.left + this.element.outerWidth() / 2
                                        - containerWidth / 2;
                if (containerLeft < 0) {