`EventSourceResponse`는 `fastapi.sse`에서 임포트합니다:

{* ../../docs_src/server_sent_events/tutorial001_py310.py ln[1:25] hl[4,22] *}

각 `yield`된 항목은 JSON으로 인코딩되어 SSE 이벤트의 `data:` 필드로 전송됩니다.

반환 타입을 `AsyncIterable[Item]`으로 선언하면 FastAPI가 이를 사용해 데이터를 Pydantic으로 **검증**, **문서화**, **직렬화**합니다.

{* ../../docs_src/server_sent_events/tutorial001_py310.py ln[1:25] hl[10:12,23] *}

/// tip | 팁

We can instead create an input model with the plaintext password and an output model without it:

{* ../../docs_src/response_model/tutorial003_py310.py hl[9,11,16] *}

Here, even though our *path operation function* is returning the same input user that contains the password:

{* ../../docs_src/response_model/tutorial003_py310.py hl[24] *}

...we declared the `response_model` to be our model `UserOut`, that doesn't include the password:

{* ../../docs_src/response_model/tutorial003_py310.py hl[9,11,16] *}

Aqui, embora nossa *função de operação de rota* esteja retornando o mesmo usuário de entrada que contém a senha:

{* ../../docs_src/response_model/tutorial003_py310.py hl[24] *}

...declaramos o `response_model` como nosso modelo `UserOut`, que não inclui a senha:

{* ../../docs_src/response_model/tutorial003_py310.py hl[22] *}

{* ../../docs_src/response_model/tutorial003_py310.py hl[9,11,16] *}

Burada *path operation function* password içeren aynı input user’ı döndürüyor olsa bile:

{* ../../docs_src/response_model/tutorial003_py310.py hl[24] *}

...`response_model` olarak, password’ü içermeyen `UserOut` modelimizi declare ettik:

{* ../../docs_src/response_model/tutorial003_py310.py hl[22] *}

但若你在進階情境中需要，可以這樣加入自訂標頭：

{* ../../docs_src/handling_errors/tutorial002_py310.py hl[14] *}

## 安裝自訂例外處理器 { #install-custom-exception-handlers }

你可以使用 [Starlette 的相同例外工具](https://www.starlette.dev/exceptions/) 來加入自訂例外處理器。

假設你有一個自訂例外 `UnicornException`，你（或你使用的函式庫）可能會 `raise` 它。

而你想用 FastAPI 全域處理這個例外。

你可以使用 `@app.exception_handler()` 加入自訂例外處理器：

{* ../../docs_src/handling_errors/tutorial003_py310.py hl[5:7,13:18,24] *}

///

## Кілька моделей { #multiple-models }

Ось загальна ідея того, як можуть виглядати моделі з їхніми полями пароля та місцями використання:

{* ../../docs_src/extra_models/tutorial001_py310.py hl[7,9,14,20,22,27:28,31:33,38:39] *}

### Про `**user_in.model_dump()` { #about-user-in-model-dump }

#### `.model_dump()` у Pydantic { #pydantics-model-dump }

`user_in` - це модель Pydantic класу `UserIn`.

{* ../../docs_src/response_model/tutorial003_py310.py hl[9,11,16] *}

Aquí, aunque nuestra *path operation function* está devolviendo el mismo usuario de entrada que contiene la contraseña:

{* ../../docs_src/response_model/tutorial003_py310.py hl[24] *}

...hemos declarado el `response_model` para ser nuestro modelo `UserOut`, que no incluye la contraseña:

{* ../../docs_src/response_model/tutorial003_py310.py hl[9,11,16] *}

Obwohl unsere *Pfadoperation-Funktion* hier denselben `user` von der Eingabe zurückgibt, der das Passwort enthält:

{* ../../docs_src/response_model/tutorial003_py310.py hl[24] *}

... haben wir deklariert, dass `response_model` das Modell `UserOut` ist, welches das Passwort nicht enthält:

{* ../../docs_src/path_params/tutorial005_py310.py hl[17] *}

#### *Enumerations-Wert* erhalten { #get-the-enumeration-value }

Den tatsächlichen Wert (in diesem Fall ein `str`) erhalten Sie via `model_name.value`, oder generell, `your_enum_member.value`:

{* ../../docs_src/path_params/tutorial005_py310.py hl[20] *}

/// tip | Tipp

{* ../../docs_src/path_params/tutorial005_py310.py hl[17] *}

#### *Enumeration Value*'yu Alalım { #get-the-enumeration-value }

Gerçek değeri (bu durumda bir `str`) `model_name.value` ile veya genel olarak `your_enum_member.value` ile alabilirsiniz:

{* ../../docs_src/path_params/tutorial005_py310.py hl[20] *}

/// tip | İpucu