*
     * <p>If the graph is directed, the resultant edge will be directed; otherwise, it will be
     * undirected.
     *
     * <p>If this graph is directed, {@code endpoints} must be ordered.
     *
     * <p>Values do not have to be unique. However, values must be non-null.
     *
     * <p>If either or both endpoints are not already present in this graph, this method will

     *
     * <p>If the graph is directed, the resultant edge will be directed; otherwise, it will be
     * undirected.
     *
     * <p>If this graph is directed, {@code endpoints} must be ordered.
     *
     * <p>Values do not have to be unique. However, values must be non-null.
     *
     * <p>If either or both endpoints are not already present in this graph, this method will

            ImmutableList.<V>asImmutableList(values));
    }
  }

  /**
   * Returns a builder that creates immutable sorted maps whose keys are ordered by their natural
   * ordering. The sorted maps use {@link Ordering#natural()} as the comparator.
   */
  public static <K extends Comparable<?>, V> Builder<K, V> naturalOrder() {
    return new Builder<>(Ordering.natural());

        this.docId = value;
    }

    public Integer getOrder() {
        checkSpecifiedProperty("order");
        return order;
    }

    public void setOrder(Integer value) {
        registerModifiedProperty("order");
        this.order = value;
    }

    public String getQueryId() {
        checkSpecifiedProperty("queryId");
        return convertEmptyToNull(queryId);

col-12{-ms-flex:0 0 100%;flex:0 0 100%;max-width:100%}.order-first{-ms-flex-order:-1;order:-1}.order-last{-ms-flex-order:13;order:13}.order-0{-ms-flex-order:0;order:0}.order-1{-ms-flex-order:1;order:1}.order-2{-ms-flex-order:2;order:2}.order-3{-ms-flex-order:3;order:3}.order-4{-ms-flex-order:4;order:4}.order-5{-ms-flex-order:5;order:5}.order-6{-ms-flex-order:6;order:6}.order-7{-ms-flex-order:7;order:7}.order-8{-ms-flex-order:8;order:8}.order-9{-ms-flex-order:9;order:9}.order-10{-ms-flex-order:10...

col-12{-ms-flex:0 0 100%;flex:0 0 100%;max-width:100%}.order-first{-ms-flex-order:-1;order:-1}.order-last{-ms-flex-order:13;order:13}.order-0{-ms-flex-order:0;order:0}.order-1{-ms-flex-order:1;order:1}.order-2{-ms-flex-order:2;order:2}.order-3{-ms-flex-order:3;order:3}.order-4{-ms-flex-order:4;order:4}.order-5{-ms-flex-order:5;order:5}.order-6{-ms-flex-order:6;order:6}.order-7{-ms-flex-order:7;order:7}.order-8{-ms-flex-order:8;order:8}.order-9{-ms-flex-order:9;order:9}.order-10{-ms-flex-order:10...

	// Otherwise same set of buckets get scanned across erasure sets always.
	// at any given point in time. This allows different buckets to be scanned
	// in different order per erasure set, this wider spread is needed when
	// there are lots of buckets with different order of objects in them.
	r := rand.New(rand.NewSource(time.Now().UnixNano()))
	permutes := r.Perm(len(buckets))
	// Add new buckets first
	for _, idx := range permutes {

    }

    @Override
    public Entry<K, V>[] createArray(int length) {
      return generator.createArray(length);
    }

    @Override
    public Iterable<Entry<K, V>> order(List<Entry<K, V>> insertionOrder) {
      return generator.order(insertionOrder);
    }

    @SuppressWarnings("unchecked")
    @Override
    public K[] createKeyArray(int length) {
      return (K[]) new Object[length];
    }

    return (Multiset<T>) iterable;
  }

  /**
   * Returns a copy of {@code multiset} as an {@link ImmutableMultiset} whose iteration order puts
   * the highest count first, with ties broken by the iteration order of the original multiset.
   *
   * @since 11.0
   */
  public static <E> ImmutableMultiset<E> copyHighestCountFirst(Multiset<E> multiset) {

      }

      @Override
      public List<String> order(List<String> insertionOrder) {
        List<String> order = new ArrayList<>();
        for (String s : insertionOrder) {
          int index = order.indexOf(s);
          if (index == -1) {
            order.add(s);
          } else {
            order.add(index, s);
          }
        }
        return order;
      }
    };
  }