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00000130  4c 47 7e c4 5e 0f 03 fc  60 9e ba 47 ea a9 9b ef  |LG~.^...`..G....|
00000140  9a 04 62 e3 db bf 30 d7  5a 1f 20 c9 4c 37 ff 0e  |..b...0.Z. .L7..|
00000150  46 d9 ce 85 c5 47 16 43  9a 89 0b 97 44 7a be 09  |F....G.C....Dz..|
00000160  5d 03 a0 b1 1f a6 ca 78  0d fb f4 1a 6d 3a ec 40  |]......x....m:.@|
00000170  1e 58 fc 67 5e bb 69 a1  ae 1d 6d bc b4 80 b9 71  |.X.g^.i...m....q|

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	}()
	return Z
}

// Exponential of a power series with constant term 0
// (nonzero constant term would make nonrational coefficients)
// bug: the constant term is simply ignored
//	Z = exp(U)
//	DZ = Z*DU
//	integrate to get Z

func Exp(U PS) PS {
	ZZ := mkPS2()
	split(Integ(one, Mul(ZZ[0], Diff(U))), ZZ)
	return ZZ[1]
}

// Substitute V for x in U, where the leading term of V is zero

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      |0N0AAAFxc9MmmwAABAMASDBGAiEAqeWK3uWt9LX1p3l0gPgNxYBB142oqtRMnMBB
      |anTKy2ICIQDrRj7PRsVyXf1QRxgE5MZl6K6XkBKbaXBlAqPpb8z2hQB3AId1v+dZ
      |fPiMQ5lfvfNu/1aNR1Y2/0q1YMG06v9eoIMPAAABcXPTJq0AAAQDAEgwRgIhANRS
      |wAmVQLXhhxbbUTSKIA6P0Q6EmNABCNSJjSK5Q0ItAiEA88hnegYqVaykbbsQSSI0
      |gP/+Odnm/Thso6HEJFXvYGcAdQB9PvL4j/+IVWgkwsDKnlKJeSvFDngJfy5ql2iZ

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// dz : http://www.nic.dz/images/pdf_nic/charte.pdf
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// ec : http://www.nic.ec/reg/paso1.asp
// Submitted by registry <******@****.***>
ec
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	}(U, Z)
	return Z
}

// Exponential of a power series with constant term 0
// (nonzero constant term would make nonrational coefficients)
// bug: the constant term is simply ignored
//	Z = exp(U)
//	DZ = Z*DU
//	integrate to get Z

func Exp(U PS) PS {
	ZZ := mkPS2()
	split(Integ(one, Mul(ZZ[0], Diff(U))), ZZ)
	return ZZ[1]
}

// Substitute V for x in U, where the leading term of V is zero

  //  [5, 6],
  //  [7, 8]
  // ]
  // and we do a Prod operation on the axis 1, we will obtain [[105, 192]].
  // The gradient will have the same shape as the input
  //     [
  //       [105/3, 192/4],
  // dz *  [105/5, 192/6],
  //       [105/7, 192/6]
  //     ]
  // If the input contains a zero, the division is impossible but
  // if we take the calculation that gave the first gradient
  // (3 * 5 * 6)/3 is equal to 5 * 6

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