* Reader#skip(long) skip} to the end of the stream, and return the total number of chars that
   * were skipped.
   *
   * <p>Note that for sources that implement {@link #lengthIfKnown} to provide a more efficient
   * implementation, it is <i>possible</i> that this method will return a different number of chars
   * than would be returned by reading all of the chars.
   *

    reverse(array, fromIndex, toIndex);
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Longs.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(long[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

 *     .url("http://publicobject.com/helloworld.txt")
 *     .build();
 * ```
 *
 * If it is only necessary to force a cached response to be validated by the server, use the more
 * efficient `max-age=0` directive instead:
 *
 * ```java
 * Request request = new Request.Builder()
 *     .cacheControl(new CacheControl.Builder()
 *         .maxAge(0, TimeUnit.SECONDS)
 *         .build())

    return file(new File(first), more);
  }

  /** Returns a {@code File} object for the given path parts. */
  private static File file(File first, String... more) {
    // not very efficient, but should definitely be correct
    File file = first;
    for (String name : more) {
      file = new File(file, name);
    }
    return file;
  }

        }
        return true; // that.size() == this.size()
      }
    }

    /**
     * Returns a lower bound for {@link #size()} based on the sizes of the backing sets.
     *
     * <p>This is more efficient than {@link #size()}, which iterates over the entire {@link
     * SetView}.
     */
    abstract int minSize();

    /**

  }

  /**
   * Runs the specified action for each distinct element in this multiset, and the number of
   * occurrences of that element. For some {@code Multiset} implementations, this may be more
   * efficient than iterating over the {@link #entrySet()} either explicitly or with {@code
   * entrySet().forEach(action)}.
   *
   * @since 21.0
   */
  default void forEachEntry(ObjIntConsumer<? super E> action) {

  }

  /**
   * Creates an empty multiset containing the given initial elements, sorted according to the
   * elements' natural order.
   *
   * <p>This implementation is highly efficient when {@code elements} is itself a {@link Multiset}.
   *
   * <p>The type specification is {@code <E extends Comparable>}, instead of the more specific

   * elements will appear in the returned list in the same order they appeared in {@code elements}.
   *
   * <p><b>Performance note:</b> According to our
   * benchmarking
   * on Open JDK 7, this method is the most efficient way to make a sorted copy of a collection.
   *
   * @throws NullPointerException if any element of {@code elements} is {@code null}
   * @since 3.0
   */
  // TODO(kevinb): rerun benchmarks including new options

   * is as close as possible to the center of the range [{@code from}, {@code to}]. Choosing the
   * value closest to the center of the range first is the most efficient strategy because it
   * minimizes the size of the subranges from which the remaining selections must be done.
   */
  private static int chooseNextSelection(

  }

  /**
   * Creates an empty multiset containing the given initial elements, sorted according to the
   * elements' natural order.
   *
   * <p>This implementation is highly efficient when {@code elements} is itself a {@link Multiset}.
   *
   * <p>The type specification is {@code <E extends Comparable>}, instead of the more specific