}

  public void testToByteArrayAndFromByteArrayRoundTrip() {
    for (Stats stats : ALL_STATS) {
      byte[] statsByteArray = stats.toByteArray();

      // Round trip to byte array and back
      assertThat(Stats.fromByteArray(statsByteArray)).isEqualTo(stats);
    }
  }

  public void testFromByteArray_withNullInputThrowsNullPointerException() {

 * {@code asMap} has a few subtleties. As long as the set of keys remains unchanged, adding or
 * removing mappings does not affect the key iteration order. However, if you remove all values
 * associated with a key and then add the key back to the multimap, that key will come last in the
 * key iteration order.
 *
 * <p>The multimap does not store duplicate key-value pairs. Adding a new key-value pair equal to an
 * existing key-value pair has no effect.
 *

    return lazyWeakCustom(stripes, WeakSafeReadWriteLock::new);
  }
  /**
   * ReadWriteLock implementation whose read and write locks retain a reference back to this lock.
   * Otherwise, a reference to just the read lock or just the write lock would not suffice to ensure
   * the {@code ReadWriteLock} is retained.
   */

/// info

If you already went through all the tutorial and came back to see more about types, a good resource is <a href="https://mypy.readthedocs.io/en/latest/cheat_sheet_py3.html" class="external-link" target="_blank">the "cheat sheet" from `mypy`</a>.

                VersionRange parentRange = versionParser.parseVersionRange(parent.getVersion());
                if (!parentRange.contains(versionParser.parseVersion(version))) {
                    // version skew drop back to resolution from the repository
                    return null;
                }

                // Validate versions aren't inherited when using parent ranges the same way as when read externally.

       * up to give roundArbitrarily equal to 2^63, so the conversion back to long overflows and
       * roundArbitrarilyAsLong is Long.MAX_VALUE. (This is the only way this condition can occur as
       * otherwise the conversion back to long pads with zero bits.) In this case we know that
       * roundArbitrarily > x. (This is important when x == Long.MAX_VALUE ==

ll==(l=v&&v.display)&&(l=_.get(e,"display")),"none"===(c=ce.css(e,"display"))&&(l?c=l:(re([e],!0),l=e.style.display||l,c=ce.css(e,"display"),re([e]))),("inline"===c||"inline-block"===c&&null!=l)&&"none"===ce.css(e,"float")&&(u||(p.done(function(){h.display=l}),null==l&&(c=h.display,l="none"===c?"":c)),h.display="inline-block")),n.overflow&&(h.overflow="hidden",p.always(function(){h.overflow=n.overflow[0],h.overflowX=n.overflow[1],h.overflowY=n.overflow[2]})),u=!1,d)u||(v?"hidden"in v&&(g=v.hidde...

   * {@code tailSet} views.
   *
   * <pre>{@code
   * NavigableSet<E> set = synchronizedNavigableSet(new TreeSet<E>());
   *  ...
   * synchronized (set) {
   *   // Must be in the synchronized block
   *   Iterator<E> it = set.iterator();
   *   while (it.hasNext()) {
   *     foo(it.next());
   *   }
   * }
   * }</pre>
   *
   * <p>or:
   *
   * <pre>{@code

       * up to give roundArbitrarily equal to 2^63, so the conversion back to long overflows and
       * roundArbitrarilyAsLong is Long.MAX_VALUE. (This is the only way this condition can occur as
       * otherwise the conversion back to long pads with zero bits.) In this case we know that
       * roundArbitrarily > x. (This is important when x == Long.MAX_VALUE ==

	// There is flow control in both directions.
	StreamHandler struct {
		// Handle an incoming request. Initial payload is sent.
		// Additional input packets (if any) are streamed to request.
		// Upstream will block when request channel is full.
		// Response packets can be sent at any time.
		// Any non-nil error sent as response means no more responses are sent.
		Handle StreamHandlerFn

		// Subroute for handler.