refreshIfEmpty();
      return delegate.size();
    }

    @Override
    /*
     * Most Multimap implementations use a List or Set (or even Multiset) for their values, in which
     * case Multimap equality works as expected. Users who use a Collection type that does not
     * implement equals(), such as most Queue implementations, will get the same behavior from our

   * array as the lesser. For example, {@code [] < ['a'] < ['a', 'b'] < ['b']}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(char[],
   * char[])}.
   *
   * @since 2.0
   */
  public static Comparator<char[]> lexicographicalComparator() {
    return LexicographicalComparator.INSTANCE;

   * lesser. For example, {@code [] < [1.0f] < [1.0f, 2.0f] < [2.0f]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(float[],
   * float[])}.
   *
   * @since 2.0
   */
  public static Comparator<float[]> lexicographicalComparator() {
    return LexicographicalComparator.INSTANCE;

   * example, {@code [] < [1L] < [1L, 2L] < [2L]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(long[],
   * long[])}.
   *
   * @since 2.0
   */
  public static Comparator<long[]> lexicographicalComparator() {
    return LexicographicalComparator.INSTANCE;

    E[] array = (E[]) elements.toArray();
    /*
     * For a Set, we guess that it contains no duplicates. That's just a guess for purpose of
     * sizing; if the Set uses different equality semantics, it might contain duplicates according
     * to equals(), and we will deduplicate those properly, albeit at some cost in allocations.
     */
    int expectedSize =

   * lesser. For example, {@code [] < [1.0] < [1.0, 2.0] < [2.0]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link Arrays#equals(double[],
   * double[])}.
   *
   * @since 2.0
   */
  public static Comparator<double[]> lexicographicalComparator() {

      if (result == -1) {
        break;
      }
      total += result;
    }
    return total;
  }

  /** Compares the contents of the two {@link InputStream}s for equality. */
  static boolean contentsEqual(InputStream in1, InputStream in2) throws IOException {
    byte[] buf1 = createBuffer();
    byte[] buf2 = createBuffer();
    while (true) {

      Comparator<? super E> comparator) {
    return new TreeSet<>(checkNotNull(comparator));
  }

  /**
   * Creates an empty {@code Set} that uses identity to determine equality. It compares object
   * references, instead of calling {@code equals}, to determine whether a provided object matches
   * an element in the set. For example, {@code contains} returns {@code false} when passed an

 * that makes `java.net.URL` unusable for many things. It shouldn't be used as a [Map] key or in a
 * [Set]. Doing so is both inefficient because equality may require a DNS lookup, and incorrect
 * because unequal URLs may be equal because of how they are hosted.
 *
 * ### Equal URLs should be equal
 *

    TypeToken<StringForFirstTypeArg<Integer>> subtype =
        new TypeToken<StringForFirstTypeArg<Integer>>() {};
    assertTrue(subtype.isSubtypeOf(supertype));

    // TODO(benyu): This should check equality to an expected value, see discussion in cl/98674873
    TypeToken<?> unused = supertype.getSubtype(subtype.getRawType());
  }

  public void testGetSubtype_baseClassWithNoTypeArgs() {