overflowed). // // The paper suggests in Section 4 that we can do an "Almost Montgomery // Multiplication" by subtracting only in the overflow case, but the // cost is very similar since the constant time subtraction tells us if // x >= m as a side effect, and taking care of the broken invariant is // highly undesirable (see https://go.dev/issue/13907). copy(x.reset(n).limbs, T[n:]) x.maybeSubtractModulus(choice(c), m) // The following specialized cases follow the exact same algorithm, but // optimized...