if (ranges.isEmpty()) {
      return ImmutableMap.of();
    }
    RegularImmutableSortedSet<Range<K>> rangeSet =
        new RegularImmutableSortedSet<>(ranges.reverse(), Range.<K>rangeLexOrdering().reverse());
    return new ImmutableSortedMap<>(rangeSet, values.reverse());
  }

  @Override
  public ImmutableRangeMap<K, V> subRangeMap(Range<K> range) {
    if (checkNotNull(range).isEmpty()) {

        getUpperEndpoint(),
        getUpperBoundType());
  }

  @LazyInit private transient @Nullable GeneralRange<T> reverse;

  /** Returns the same range relative to the reversed comparator. */
  GeneralRange<T> reverse() {
    GeneralRange<T> result = reverse;
    if (result == null) {
      result =
          new GeneralRange<>(
              reverseComparator(comparator),

import com.google.common.annotations.GwtIncompatible;
import com.google.common.annotations.J2ktIncompatible;
import java.io.Serializable;
import java.util.Iterator;

/** An ordering that uses the reverse of the natural order of the values. */
@GwtCompatible
final class ReverseNaturalOrdering extends Ordering<Comparable<?>> implements Serializable {
  static final ReverseNaturalOrdering INSTANCE = new ReverseNaturalOrdering();

    }

    // --- as(Class, DLSequence, int) ---

    @Test
    void testAs_DLSequence_RecursiveBug() {
        // This test exposes a recursive bug in the current implementation
        // The method calls itself, leading to a StackOverflowError.
        ASN1EncodableVector vector = new ASN1EncodableVector();
        vector.add(new ASN1Integer(10));

 *       <i>any</i> eight bits could be consistently used.
 *   <li><b>cryptographic:</b> certain hash functions such as {@link Hashing#sha512} are designed to
 *       make it as infeasible as possible to reverse-engineer the input that produced a given hash
 *       code, or even to discover <i>any</i> two distinct inputs that yield the same result. These

 *       <i>any</i> eight bits could be consistently used.
 *   <li><b>cryptographic:</b> certain hash functions such as {@link Hashing#sha512} are designed to
 *       make it as infeasible as possible to reverse-engineer the input that produced a given hash
 *       code, or even to discover <i>any</i> two distinct inputs that yield the same result. These

                }
            }
        }

        final Object recursive = dataMap.remove(getParamValue(paramMap, "field.recursive", "recursive"));
        if (recursive == null || Constants.FALSE.equalsIgnoreCase(recursive.toString())) {
            return 1L;
        }
        if (Constants.TRUE.equalsIgnoreCase(recursive.toString())) {
            return -1L;
        }

        return 1L;
    }

    @Override
    protected List<String> create(String[] elements) {
      List<String> list = asList(elements);
      Collections.reverse(list);
      return ImmutableList.copyOf(list).reverse();
    }
  }

  public static class ImmutableListHeadSubListGenerator extends TestStringListGenerator {
    @Override
    protected List<String> create(String[] elements) {

    Arrays.sort(array, fromIndex, toIndex);
    reverse(array, fromIndex, toIndex);
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Longs.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(long[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

    return offset + size;
  }

  /**
   * Returns a view of this immutable list in reverse order. For example, {@code ImmutableList.of(1,
   * 2, 3).reverse()} is equivalent to {@code ImmutableList.of(3, 2, 1)}.
   *
   * @return a view of this immutable list in reverse order
   * @since 7.0
   */
  public ImmutableList<E> reverse() {
    return (size() <= 1) ? this : new ReverseImmutableList<E>(this);
  }