.glyphicon,.fc-color-picker>li .ion{transition:-webkit-transform linear .3s;transition:transform linear .3s;transition:transform linear .3s,-webkit-transform linear .3s}.fc-color-picker>li .fa:hover,.fc-color-picker>li .fab:hover,.fc-color-picker>li .far:hover,.fc-color-picker>li .fas:hover,.fc-color-picker>li .glyphicon:hover,.fc-color-picker>li .ion:hover{-webkit-transform:rotate(30deg);transform:rotate(30deg)}#add-new-event{transition:all linear .3s}.external-event{box-shadow:0 0 1px rgba(0,0,0,.125),0...

// in which those blocks will appear in the assembly output.
func layout(f *Func) {
	f.Blocks = layoutOrder(f)
}

// Register allocation may use a different order which has constraints
// imposed by the linear-scan algorithm.
func layoutRegallocOrder(f *Func) []*Block {
	// remnant of an experiment; perhaps there will be another.
	return layoutOrder(f)
}

func layoutOrder(f *Func) []*Block {

//   is widened to a full integer array.)

// The overall runtime of this code is linear in the input size:
// it runs a sequence of linear passes to reduce the problem to
// a subproblem at most half as big, invokes itself recursively,
// and then runs a sequence of linear passes to turn the answer
// for the subproblem into the answer for the original problem.

    }

    img {
        max-width: 100% !important
    }

    pre, blockquote, img {
        page-break-inside: avoid
    }
}

header .navbar {
    background-image: linear-gradient(to right, #466BB0, #68AAF7);
    box-shadow: 0 0 2px 2px rgba(0, 0, 0, 0.14), 0 2px 4px 2px rgba(0, 0, 0, 0.28);
    padding-top: .2em;
    padding-bottom: .2em
}

header .navbar .logo {

	// from https://en.wikipedia.org/wiki/UTF-16
	{'\u007A', false},     // LATIN SMALL LETTER Z
	{'\u6C34', false},     // CJK UNIFIED IDEOGRAPH-6C34 (water)
	{'\uFEFF', false},     // Byte Order Mark
	{'\U00010000', false}, // LINEAR B SYLLABLE B008 A (first non-BMP code point)
	{'\U0001D11E', false}, // MUSICAL SYMBOL G CLEF
	{'\U0010FFFD', false}, // PRIVATE USE CHARACTER-10FFFD (last Unicode code point)

	{rune(0xd7ff), false}, // surr1-1

	// Insert regardless of whether we have a match in m.pcs.
	// Even if we have a match, we want to keep the newest version
	// of that stack, since we're much more likely tos see it again
	// as we iterate through the trace linearly. Simultaneously, we
	// are likely to never see the old stack again.
	m.pcs[pcs] = stack
	m.stacks[stack] = rec
	return rec
}

func (m *stackMap) profile() []traceviewer.ProfileRecord {

	// In both cases the algorithm is a linear scan over the two
	// lists - T's methods and V's methods - simultaneously.
	// Since method tables are stored in a unique sorted order
	// (alphabetical, with no duplicate method names), the scan
	// through V's methods must hit a match for each of T's
	// methods along the way, or else V does not implement T.
	// This lets us run the scan in overall linear time instead of

				if r == r1 {
					return 0
				}
			}
		}
		return noMatch

	case 2:
		if r >= rune[0] && r <= rune[1] {
			return 0
		}
		return noMatch

	case 4, 6, 8:
		// Linear search for a few pairs.
		// Should handle ASCII well.
		for j := 0; j < len(rune); j += 2 {
			if r < rune[j] {
				return noMatch
			}
			if r <= rune[j+1] {
				return j / 2
			}
		}

> li .fa,\n.fc-color-picker > li .fas,\n.fc-color-picker > li .far,\n.fc-color-picker > li .fab,\n.fc-color-picker > li .glyphicon,\n.fc-color-picker > li .ion {\n  transition: -webkit-transform linear .3s;\n  transition: transform linear .3s;\n  transition: transform linear .3s, -webkit-transform linear .3s;\n}\n\n.fc-color-picker > li .fa:hover,\n.fc-color-picker > li .fas:hover,\n.fc-color-picker > li .far:hover,\n.fc-color-picker > li .fab:hover,\n.fc-color-picker > li .glyphicon:hover,\n.fc-color-picker...

  //
  // Proof: For unary einsum equations involving only transpose ("ij->ji") and
  //   traces ("ii->i"), the linear mapping's Jacobian at input x is given
  //   by the function itself. We can verify that the linear map given by the
  //   VJP are einsums with the equations "ji->ij" and "i->ii" respectively,
  //   where the latter represents 'un-tracing', or filling the diagonal with