*/

    @Override
    public int hashCode() {
        return this.addr.hashCode();
    }

    /**
     * Compare two addresses for equality. Two <code>UniAddress</code>s are equal
     * if they are both <code>UniAddress</code>' and refer to the same IP address.
     */
    @Override
    public boolean equals(final Object obj) {

 *
 * <p>Each of the {@code standard} methods, where appropriate, uses the set's comparator (or the
 * natural ordering of the elements, if there is no comparator) to test element equality. As a
 * result, if the comparator is not consistent with equals, some of the standard implementations may
 * violate the {@code Set} contract.
 *

}

// GetValidatedDNUnderBaseDN checks if the given DN exists in the LDAP
// directory.
//
// The `NormDN` value returned here in the search result may not be equal to the
// input DN, as LDAP equality is not a simple Golang string equality. However,
// we assume the value returned by the LDAP server is canonical. Additionally,
// the attribute type names in the DN are lower-cased.
//
// Return values:
//

    public static boolean isVersionGreaterOrEqual(String modelVersion, String targetVersion) {
        if (modelVersion == null || targetVersion == null) {
            return false;
        }

        // Handle exact equality first
        if (modelVersion.equals(targetVersion)) {
            return true;
        }

        // For now, handle the specific cases we need
        if (MODEL_VERSION_4_1_0.equals(targetVersion)) {

  @Override
  public Set<E> edgesConnecting(N nodeU, N nodeV) {
    NetworkConnections<N, E> connectionsU = checkedConnections(nodeU);
    if (!allowsSelfLoops && nodeU == nodeV) { // just an optimization, only check reference equality
      return ImmutableSet.of();
    }
    checkArgument(containsNode(nodeV), NODE_NOT_IN_GRAPH, nodeV);
    return nodePairInvalidatableSet(connectionsU.edgesConnecting(nodeV), nodeU, nodeV);
  }

  @Override

        // Why? The second half of condition2 requires that nodeV equals other.nodeU.
        // We already know that nodeU equals other.nodeU. Combined with the earlier statement,
        // and the transitive property of equality, this implies that nodeU equals nodeV.
        // If nodeU equals nodeV, condition1 == condition2, so checking condition1 is sufficient.
        return nodeV().equals(other.nodeV());
      }

    1.0,
    Math.PI,
    (double) Integer.MAX_VALUE,
    (double) Long.MAX_VALUE,
    Double.MAX_VALUE,
    Double.POSITIVE_INFINITY,
    Double.NaN,
    Float.MAX_VALUE,
  };

  /** The notion of equality used by AtomicDouble */
  static boolean bitEquals(double x, double y) {
    return Double.doubleToRawLongBits(x) == Double.doubleToRawLongBits(y);
  }

  static void assertBitEquals(double x, double y) {

            .resolveType(subtype));
  }

  public <T> void testWhere_mapFromBoundedWildcard() {
    Type subtype = new TypeCapture<TypedKeyMap<T>>() {}.capture();
    // TODO(benyu): This should check equality to an expected value, see discussion in cl/98674873
    Type unused =
        new TypeResolver()
            .where(
                new TypeCapture<Map<Integer, T>>() {}.capture(),

        SecurityBlob right = new SecurityBlob(b);

        // Act & Assert
        assertTrue(left.equals(right), "Blobs with equal content should be equal");
        assertTrue(right.equals(left), "Equality should be symmetric for identical content");
    }

    // Demonstrates observed equals() asymmetry when this is shorter than argument
    @Test

   * signed.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays
   * support only identity equality), but it is consistent with {@link
   * java.util.Arrays#equals(byte[], byte[])}.
   *
   * @since 2.0
   */
  public static Comparator<byte[]> lexicographicalComparator() {