of that Motion or Thing at its Incidence on that space; and of the
square of the perpendicular velocity which that Motion or Thing would
have at its Emergence, if at its Incidence its perpendicular velocity
was infinitely little.

And the same Proposition holds true of any Motion or Thing
perpendicularly retarded in its passage through that space, if instead
of the sum of the two Squares you take their difference. The

// If parsing fails or an integer overflow occurs, err will be set.
func (p *parser) parseNumeric(b []byte) int64 {
	// Check for base-256 (binary) format first.
	// If the first bit is set, then all following bits constitute a two's
	// complement encoded number in big-endian byte order.
	if len(b) > 0 && b[0]&0x80 != 0 {
		// Handling negative numbers relies on the following identity:
		//	-a-1 == ^a
		//

the refracting Angle of the Prism be turned upwards, so that the Paper may seem to be lifted upwards by the Refraction, its blue half will be lifted higher by the Refraction than its red half. But if the refracting Angle of the Prism be turned downward, so that the Paper may seem to be carried lower by the Refraction, its blue half will be carried something lower thereby than its red half. Wherefore in both Cases the Light which comes from the blue half of the Paper through the Prism to the Eye, does...

   */
  public static boolean isPowerOfTwo(int x) {
    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned integers, and 0 otherwise. Assumes that x - y fits into
   * a signed int. The implementation is branch-free, and benchmarks suggest it is measurably (if
   * narrowly) faster than the straightforward ternary expression.
   */
  @VisibleForTesting

	// NodeName is a request to schedule this pod onto a specific node. If it is non-empty,
	// the scheduler simply schedules this pod onto that node, assuming that it fits resource
	// requirements.
	// +optional
	NodeName string `json:"nodeName,omitempty" protobuf:"bytes,10,opt,name=nodeName"`
	// Host networking requested for this pod. Use the host's network namespace.

  public static boolean isPowerOfTwo(long x) {
    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned longs, and 0 otherwise. Assumes that x - y fits into a
   * signed long. The implementation is branch-free, and benchmarks suggest it is measurably faster
   * than the straightforward ternary expression.
   */
  @VisibleForTesting

   */
  public static boolean isPowerOfTwo(int x) {
    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned integers, and 0 otherwise. Assumes that x - y fits into
   * a signed int. The implementation is branch-free, and benchmarks suggest it is measurably (if
   * narrowly) faster than the straightforward ternary expression.
   */
  @VisibleForTesting

	// A consumer continues to own a slot outside this range until
	// it nils the slot, at which point ownership passes to the
	// producer.
	//
	// The head index is stored in the most-significant bits so
	// that we can atomically add to it and the overflow is
	// harmless.
	headTail atomic.Uint64

	// vals is a ring buffer of interface{} values stored in this
	// dequeue. The size of this must be a power of 2.
	//

	// delayed until a Pod gets scheduled that needs the ResourceClaim. The
	// scheduler will consider all resource requirements of that Pod and
	// trigger allocation for a node that fits the Pod.
	AllocationModeWaitForFirstConsumer AllocationMode = "WaitForFirstConsumer"

	// When a ResourceClaim has AllocationModeImmediate, allocation starts
	// as soon as the ResourceClaim gets created. This is done without

		if !d.scanner.Scan() {
			err := d.scanner.Err()
			if err == nil {
				err = io.EOF
			}
			return 0, err
		}
		out := d.scanner.Bytes()
		d.remaining = out
		left = len(out)
	}

	// fits within data
	if left <= len(data) {
		copy(data, d.remaining)
		d.remaining = nil
		return left, nil
	}

	// caller will need to reread
	copy(data, d.remaining[:len(data)])